Statistics

A TI-84-focused statistics companion with concise notes, worked examples, and quick references for class, study, and review.

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Module 1: Introduction, Data Collection, Sampling, and Experimental Design

Students learn the language of statistics, study design, sampling methods, bias, and experiment design.

Section 1.1

Introduction to the Practice of Statistics

Use the basic vocabulary of statistics and classify variables correctly.

Quick reference

  • Statistics is the science of collecting, organizing, summarizing, and analyzing information to answer questions.
  • Data are the information collected from individuals. A variable is the characteristic being recorded, and the data are the observed values of that variable.
  • The process of statistics usually starts with a research objective, then data are collected, summarized, and used for inference when appropriate.
  • Statistics has two main branches.
    • Descriptive statistics organizes and summarizes data using tables, graphs, or numerical summaries.
    • Inferential statistics uses sample data to draw conclusions about a population and reports uncertainty.
  • Three terms identify who or what is being studied.
    • A population is the entire group being studied.
    • A sample is a subset of that population.
    • An individual is one person or object in the group being studied.
  • A numerical summary is named according to whether it describes a population or a sample.
    • A parameter is a numerical summary of a population.
    • A statistic is a numerical summary of a sample.
  • Variables can be qualitative or quantitative.
    • Qualitative variables describe categories.
    • Quantitative variables are numerical values where arithmetic has meaning, so number labels such as ZIP codes or coded weekdays are not treated as quantitative.
  • Quantitative variables can be discrete or continuous.
    • Discrete quantitative variables come from counting.
    • Continuous quantitative variables come from measurement and can take values between two measured values.
  • The four levels of measurement describe how the values of a variable can be compared.
    • Nominal means names only.
    • Ordinal means categories with an order.
    • Interval means differences can be compared, but zero is not a true none.
    • Ratio means differences and ratios make sense because zero is a true none.
Example 1. Fill in each blank using statistics, descriptive statistics, inferential statistics, statistic, parameter, sample, population, or individual. Use each term once.
  1. A numerical summary of a sample is a __________.
  2. Organizing and summarizing data with tables, graphs, or numerical summaries is __________.
  3. The science of collecting, organizing, summarizing, and analyzing information to answer questions is __________.
  4. A subset of the group being studied is a __________.
  5. Using sample data to draw conclusions about a population is __________.
  6. One person or object in the group being studied is an __________.
  7. A numerical summary of a population is a __________.
  8. The entire group being studied is the __________.
Example 2. A researcher surveys 420 adults from a city to estimate the percent of all adults in the city who support a new park. Identify the population, sample, individual, variable, and whether 61% from the survey is a statistic or parameter.
Example 3. The table shows information collected from five campus parking spaces. Identify the individuals, variables, and one row of data.
Space Payment method Minutes parked Side of campus Space number
A Card 42 North 18
B Cash 25 South 11
C App 60 North 22
D Card 15 West 7
E App 38 South 14
Example 4. Classify each variable as qualitative, quantitative discrete, or quantitative continuous: eye color, number of siblings, commute time, phone brand, ZIP code, day of the week coded as 1 through 7, number of text messages sent yesterday, and height.
Example 5. Determine the level of measurement: hair color, movie rating from one to five stars, year of birth, and weight.
Example 6. A summary gives the ages of students in one class. A separate statement says the average age from that class estimates the average age of all students at the college. Which part is descriptive and which part is inferential?
Example 7. A news organization surveys 1007 adults and finds that 38% believe a government agency wastes at least half of its budget. The organization reports a margin of error of 6% at a 90% confidence level. Identify the research objective, the descriptive statistic, and a reasonable inference.
Section 1.2

Observational Studies versus Designed Experiments

Distinguish observational studies from experiments and avoid unsupported causal claims.

Quick reference

  • Two common ways to collect data are observational studies and designed experiments.
    • An observational study measures characteristics without trying to change the subjects.
    • A designed experiment assigns treatments and observes the response, while controlling other conditions when possible.
  • Two variables describe a possible relationship in a study.
    • The explanatory variable may help explain changes in the response variable.
    • The response variable is the outcome being measured.
  • Experiments use treatments and experimental units.
    • A treatment is the condition applied in an experiment.
    • An experimental unit is the person or object receiving the treatment.
  • Common types of observational studies differ in when and how information is collected.
    • Cross-sectional studies collect information at one point in time or over a short time period.
    • Case-control studies are retrospective: researchers look back or use existing records to compare individuals with a condition to similar individuals without it.
    • Cohort studies are prospective: researchers follow a group over time and record what happens.
  • Other variables can make a relationship difficult to interpret.
    • Confounding happens when the effects of two or more explanatory variables are mixed together.
    • A lurking variable was not included in the study but may affect the response and may be related to an explanatory variable in the study.
    • A confounding variable was included in the study, but its effect cannot be separated from the effect of another explanatory variable.
  • No type of observational study is always best. The research question, available data, time, and cost help determine which type is most appropriate.
  • Observational studies can show association, but they do not prove cause and effect by themselves. A well-designed experiment gives stronger evidence for cause and effect.
Example 1. Scenario A: A researcher records coffee intake and sleep hours for 200 adults without assigning coffee amounts. Scenario B: Students are randomly assigned to either use a new study app or not use it, then their exam scores are compared. Which scenario is observational, and which is an experiment?
Example 2. Researchers study whether study time is related to exam score. Identify the explanatory variable and response variable.
Example 3. Classify each observational study as cross-sectional, case-control, or cohort: (a) A survey asks adults about their current exercise habits today. (b) Researchers compare patients with kidney failure to similar patients without kidney failure and check past diabetes records. (c) Researchers follow 1806 adults for 7 years to see who develops high blood pressure.
Example 4. Which study is retrospective, and which is prospective? Study A uses past medical records to compare people with and without a disease. Study B follows a group of people for 10 years and records who develops the disease. Is one study type always better than the other?
Example 5. Researchers study the relationship between exercise and stress. They include sleep in the study, but people who sleep more also tend to exercise more, so the separate effects of sleep and exercise cannot be determined. The researchers do not record workload, which may affect both exercise habits and stress. Identify the confounding variable, the lurking variable, and the safest conclusion.
Example 6. Researchers find that children living near high-tension wires have a higher rate of leukemia than children who do not live near high-tension wires. Can the researchers conclude that the wires cause leukemia?
Example 7. Office workers are randomly assigned to take either meditation breaks or walking breaks every 2 hours for one month. Their stress levels are compared. Identify the treatment, experimental units, explanatory variable, and response variable.
Section 1.3

Simple Random Sampling

Recognize and create simple random samples.

Quick reference

  • Data may be collected from a census or a sample.
    • A census collects data from every individual in the population.
    • A sample collects data from only part of the population.
  • Random sampling uses chance to select individuals. A simple random sample of size \(n\) goes further: every possible group of \(n\) individuals has the same chance of being selected.
  • A sampling frame is the list of all individuals available for selection. Give each individual one unique number; for a random number table, use the same number of digits, such as 01 through 40.
  • Sampling may be done with or without replacement.
    • Sampling without replacement means a selected individual cannot be chosen again.
    • Sampling with replacement means the individual is returned and may be chosen again.
  • A random number table can be used to select a simple random sample.
    • Choose a starting position and direction, read digits in groups that match the assigned numbers, and keep valid numbers until the sample is complete.
    • Skip 00, numbers outside the population range, and repeated numbers when sampling without replacement.
  • Random selection helps reduce selection bias.
  • TI-84: press MATH → PRB to access random-integer commands.
    • Use randInt( to generate random integers. For sampling without replacement, ignore repeated values.
    • Use randIntNoRep( when available to generate different values without replacement.
Example 1. A school has 1200 students. Plan A surveys all 1200 students. Plan B numbers the students from 1 to 1200 and uses random integers to select 80 different students. Identify the census, the sample, and the sampling method used in Plan B.
Example 2. Which methods could produce a simple random sample of 3 books from a list of 9? (a) Number the books and use a random number generator. (b) Put one slip for each book in a container and draw three without looking. (c) Choose the first three books alphabetically. (d) Ask someone to choose the three best books.
Example 3. Ava, Ben, Cora, and Diego are candidates for a two-person committee. List all possible samples of size 2 when sampling without replacement. What is the probability of selecting Ava and Cora? If Ava's name is returned before the second draw, is that with or without replacement, and could Ava be selected twice?
Example 4. A club numbers its 40 members from 01 through 40. Starting with the upper-left entry and reading across each row, use the random number pairs to select a simple random sample of 5 members without replacement. Explain which entries are skipped.
Random number pairs
074412
120036
412503
Example 5. A company numbers its 50 employees from 1 to 50 and wants a simple random sample of 6 employees without replacement. The TI-84 command randInt(1,50,8) returns {31, 12, 4, 12, 48, 19, 27, 6}. Which employees are selected? Which command can avoid repeated values when it is available?
Example 6. A college wants the opinions of all enrolled students. Why is randomly selecting students from the complete enrollment list preferred over asking for volunteers, and what is the sampling frame?
Section 1.4

Other Effective Sampling Methods

Classify and compare stratified, cluster, systematic, and convenience sampling.

Quick reference

  • Stratified sampling separates the population into nonoverlapping groups, called strata, based on a shared characteristic. A random sample is selected from every stratum.
    • The number selected from each stratum may be the same or may be proportional to the stratum's size.
    • In a proportional sample, a group containing 30% of the population supplies 30% of the sample.
    • Stratified sampling guarantees representation from every stratum.
  • Cluster sampling separates the population into groups, randomly selects some entire groups, then includes everyone in the selected groups.
    • Cluster sampling can reduce travel, time, or cost when the groups are spread out.
  • To distinguish the methods, remember: stratified sampling selects some individuals from every group; cluster sampling selects everyone from some groups.
  • Systematic sampling selects every \(k\)th individual after a random starting position.
    • To obtain a sample of size \(n\) from a population of size \(N\), use \(k=\lfloor N/n\rfloor\), randomly choose \(p\) from 1 through \(k\), and select positions \(p\), \(p+k\), \(p+2k\), and so on through \(p+(n-1)k\).
    • A systematic sample uses a random start, but it is not a simple random sample because only samples following the every-\(k\)th pattern can be selected.
  • Convenience sampling uses individuals who are easy to reach and is not a random sampling method.
    • A voluntary response sample is a common convenience sample in which people choose whether to participate.
Sampling Methods at a Glance
Visual comparison of simple random, stratified, cluster, and systematic sampling

The same population of 24 people is shown four ways, with six selected people in each sample. Simple random sampling selects six scattered individuals without grouping. Stratified sampling selects two individuals from each of three strata. Cluster sampling selects two entire clusters of three people. Systematic sampling selects every fourth person after a random starting position.

Example 1. Identify the sampling method in each situation. (a) A college numbers all students and randomly selects 160 different numbers. (b) The college randomly selects 40 freshmen, 40 sophomores, 40 juniors, and 40 seniors. (c) It randomly selects 8 classrooms and surveys every student in those rooms. (d) A quality checker inspects every 25th item after a random start. (e) A researcher surveys students who are eating in the nearest dining hall.
Example 2. A company has 120 day-shift employees, 80 evening-shift employees, and 40 night-shift employees. It wants a proportional stratified sample of 24 employees. Complete the table, then determine how many employees should be randomly selected from each shift.
ShiftPopulation sizePercent of populationNumber sampled
Day120
Evening80
Night40
Example 3. A university wants information about students living in its 12 residence halls. Plan A randomly selects 10 students from every residence hall. Plan B randomly selects 3 residence halls and surveys every student in those halls. Identify each method and explain the key difference.
Example 4. A population list contains \(N=96\) people, and a systematic sample of \(n=8\) people is needed. Find \(k\). If the random starting position is \(p=5\), list the people selected.
Example 5. Plan A randomly selects 8 different identification numbers from 1 through 96. Plan B randomly chooses a starting position from 1 through 12, then selects every 12th person. Which plan is a simple random sample, and which is a systematic sample?
Example 6. A website posts a poll and lets anyone answer. What sampling concern is present?
Section 1.5

Bias in Sampling

Identify common sources of bias and improve sampling plans.

Quick reference

  • Bias occurs when a method systematically produces results that do not accurately represent the population.
  • The three main sources of bias are sampling bias, nonresponse bias, and response bias.
  • Sampling bias occurs when the method used to select individuals tends to favor one part of the population over another.
    • Undercoverage occurs when a group in the population is left out or represented too little in the sample.
    • Voluntary response bias occurs when people choose whether to participate. People with strong opinions may be more likely to respond.
  • Nonresponse bias occurs when selected individuals who do not respond differ in an important way from those who do respond. A low response rate creates concern, but nonresponse causes bias when the two groups differ.
  • Response bias occurs when people respond, but their answers do not reflect their true beliefs or behavior.
    • Wording bias is caused by leading, loaded, or unbalanced wording. Survey questions should be written in a neutral, balanced way.
    • Interviewer influence or pressure can affect how a person answers.
    • Sensitive questions can lead people to misrepresent their beliefs or behavior.
    • The order of questions or answer choices can influence responses.
  • To distinguish the main sources, ask: Who had a chance to be selected? Who was selected but did not respond? Did the responses reflect the truth? These questions point to sampling bias, nonresponse bias, and response bias, respectively.
  • Callbacks, alternate contact methods, and rewards or incentives can reduce nonresponse. Simply increasing the number contacted does not correct a biased response pattern.
  • Neutral wording, impartial administration, anonymity when appropriate, and rotating question or answer order can reduce response bias.
  • Sampling error is the natural sample-to-sample difference that occurs because only part of the population is observed; it is not the same as sampling bias. Undercoverage, nonresponse, response bias, and data-entry mistakes are nonsampling errors and can occur even in a census.
Example 1. Fill in each blank using bias, sampling bias, nonresponse bias, or response bias. Use each term once.
  1. __________ occurs when the method used to select individuals tends to favor one part of the population over another.
  2. __________ occurs when survey answers do not reflect the respondents' true beliefs or behavior.
  3. A sample has __________ when its results systematically fail to represent the population accurately.
  4. __________ occurs when selected individuals who do not respond differ from those who respond.
Example 2. Identify the most specific source of bias in each situation.
  1. A store manager surveys the first 60 customers who enter on Saturday morning.
  2. A phone survey calls only landlines to estimate the opinions of all adults.
  3. A news website posts a poll that any visitor may choose to answer.
  4. A questionnaire is mailed to 1117 randomly selected households, but only 14 respond.
  5. A supervisor asks employees face-to-face whether they have violated company rules.
  6. A survey asks, "Do you support the wasteful new tax increase?"
Example 3. A food-court manager surveys the first 100 customers who arrive on weekday mornings. Identify the bias, explain how the method could affect the results, and improve the plan.
Example 4. A survey asks, "Do you support the wasteful new tax increase?" Identify the bias and rewrite the question more neutrally.
Example 5. Distinguish nonresponse bias from response bias. Scenario A: A mail survey is sent to 2000 randomly selected people, but only 180 respond. Scenario B: College students answer a question about study hours in front of their instructor, and some exaggerate. Identify the concern and give one remedy for each scenario.
Example 6. Scenario A: A hospital administrator asks doctors to report illicit drug use. Scenario B: A poll asks about the nation's most important problem immediately before asking respondents to rate the president's job performance. Explain the likely response bias and give a remedy for each.
Example 7. Classify each as sampling error or nonsampling error. (a) Two properly selected random samples give slightly different estimates because they contain different individuals. (b) A city census misses residents without stable housing. (c) A recorded age of 39 is entered as 93.
Section 1.6

The Design of Experiments

Identify experimental design features and explain their purpose.

Quick reference

  • An experiment deliberately applies one or more treatments to experimental units and measures a response.
    • An experimental unit is the person or object receiving a treatment. A person in an experiment may also be called a subject.
    • A factor is an explanatory variable whose effect is being studied. Its levels are the values chosen for the experiment.
    • A treatment is a specific condition applied to an experimental unit. When an experiment has several factors, a treatment is a combination of factor levels.
    • The response variable is the outcome measured after the treatment is applied.
  • Good experimental designs use control, random assignment, and replication to make treatment comparisons more reliable.
    • Control means keeping other conditions as similar as possible so the treatments are the main planned difference between groups.
    • Some variables can be controlled by holding them constant, such as giving every plant the same amount of water. Other variables, such as natural differences among people or plants, cannot be held constant; random assignment helps distribute their effects across treatment groups.
    • Random assignment uses chance to place experimental units into treatment groups. It helps balance other variables across the groups.
    • Replication means applying each treatment to multiple experimental units. Repeatedly measuring the same unit does not provide the same replication as using additional units.
  • Confounding occurs when the effect of a treatment cannot be separated from the effect of another variable. Control and random assignment help reduce confounding.
  • A control group gives a baseline for comparison, and a placebo can help separate a treatment effect from the effect of expecting a treatment.
    • A control group may receive a placebo, an existing treatment, or no treatment, depending on the experiment.
    • A placebo looks like the treatment being tested but does not contain its active ingredient.
    • The placebo effect is a response caused by a subject's expectation of receiving a treatment rather than by the treatment itself.
  • Blinding reduces the chance that knowledge of the assigned treatment will influence a subject's behavior or an evaluator's judgment.
    • In a single-blind experiment, the subjects usually do not know which treatment they receive.
    • In a double-blind experiment, neither the subjects nor the researchers who interact with them or evaluate the response know the treatment assignments.
  • Three common experimental designs differ in how the experimental units are organized before treatments are assigned.
    • Completely randomized design: randomly assign all experimental units directly to the treatments.
    • Randomized block design: first separate similar experimental units into blocks, then randomly assign treatments within every block. Blocking reduces variation caused by the characteristic used to form the blocks.
    • Matched-pairs design: compare two treatments using closely matched units or the same unit under both conditions, then compare responses within each pair.
  • Random sampling and random assignment serve different purposes.
    • Random sampling helps produce a sample that can represent the population.
    • Random assignment helps create comparable treatment groups and supports cause-and-effect conclusions from a well-designed experiment.
Experimental Designs at a Glance
Visual comparison of completely randomized, randomized block, and matched-pairs experimental designs

In a completely randomized design, all experimental units are randomly assigned directly to treatments and the treatment responses are compared. In a randomized block design, similar experimental units are first placed into blocks, then treatments are randomly assigned and treatment responses are compared within each block. In a matched-pairs design, treatments are randomly assigned to matched units or treatment order is randomized for one unit under both conditions, then the paired responses are compared.

Example 1. A study randomly assigns 90 patients to a new medication, an existing medication, or a placebo. After 8 weeks, researchers record each patient's change in systolic blood pressure. Identify the experimental units, factor, factor levels or treatments, response variable, and control group.
Example 2. A fertilizer experiment uses 60 similar plants. The plants are randomly assigned to three fertilizer amounts, all plants receive the same amount of water and light, and each fertilizer amount is applied to 20 plants. Explain how the experiment uses control, random assignment, and replication.
Example 3. In a drug study, the control group receives a placebo. Neither the patients nor the doctors evaluating the outcomes know who received the real drug. Identify the blinding and explain why the placebo and blinding are useful.
Example 4. Identify the experimental design in each situation. (a) All 60 volunteers are randomly assigned directly to one of three exercise programs. (b) Volunteers are first grouped by initial fitness level, then randomly assigned to exercise programs within each group. (c) Researchers pair people with similar ages and fitness levels, then randomly assign one person in each pair to Program A and the other to Program B.
Example 5. Twelve volunteers are numbered 01 through 12. Starting at the upper left and reading across, use the random number pairs to assign six volunteers to Treatment A. Skip invalid or repeated numbers. Assign the remaining volunteers to Treatment B. What design is this, and is this random sampling or random assignment?
Random number pairs
0803120300
1114050902
Example 6. Researchers expect a medication's effect to differ among adults ages 18-39, 40-64, and 65 or older. They form these three age groups, then randomly assign medication or placebo within every age group. Identify the design, the blocks, where random assignment occurs, and why this design may be better than assigning everyone directly to treatments.
Example 7. Both situations use matched pairs. Explain how each pair is formed and what is compared. (a) For each patient, one randomly selected area of the scalp receives a platelet-rich plasma injection and another area receives saline. Hair-density changes are measured after six months. (b) Bedrooms are paired by size and wall condition. Within each pair, one room is randomly assigned Paint A and the other Paint B, then coverage quality is measured.
Example 8. A plant-growth experiment compares two fertilizers. Researchers can give every plant the same amount of water, light, and soil, but they cannot make the plants genetically identical. Classify the variables as controllable or uncontrollable, and explain the role of random assignment.

Module 2: Organizing and Displaying Data

Students organize qualitative and quantitative data using tables and graphs, then identify misleading displays.

Section 2.1

Organizing Qualitative Data

Build and interpret frequency tables and categorical graphs.

Quick reference

  • For qualitative data, a frequency distribution lists each category and its count.
    • Raw data are the original observations before they are organized or summarized.
    • Frequency is the number of observations in a category.
    • Relative frequency is the proportion of observations in a category. Find it by dividing the category frequency by the total frequency.
    • A relative-frequency distribution lists each category with its relative frequency, written as a decimal or percent.
  • Check the totals and interpret relative frequencies in context.
    • The frequencies should total the sample size \(n\).
    • The relative frequencies should total 1, or 100%, except for a small difference caused by rounding.
    • A relative frequency of 0.36 means 36% of the observations are in that category; it does not mean 36 observations.
  • A bar graph displays qualitative categories using separated bars of equal width.
    • Place the categories on one axis and frequency or relative frequency on the other. The height of each bar gives the category's value.
    • Frequency and relative-frequency bar graphs for the same data have the same overall pattern but different vertical scales.
    • Horizontal bars are useful when category names are long.
  • Special bar graphs organize bars for a particular comparison.
    • A Pareto chart orders categories from greatest to least frequency or relative frequency.
    • A side-by-side bar graph compares the same categories across two or more groups.
    • Use relative frequencies when comparing groups of different sizes so the comparison is based on proportions rather than counts.
  • A pie chart divides one whole into sectors whose sizes represent category proportions.
    • The categories must represent nonoverlapping parts of the same whole, and their percentages should total 100%.
    • To construct a sector by hand, multiply the relative frequency by 360 degrees to find the sector angle.
    • A pie chart is not appropriate when the percentages overlap or do not represent parts of one whole.
  • Category definitions matter. A graph can give a misleading comparison when one category combines several subcategories but the others do not.
Example 1. The table shows the commute method reported by 20 students. Construct a frequency and relative-frequency distribution. Check both totals, then identify the greatest and least frequencies.
Raw commute method responses
CarBusWalkCarBike
CarCarBusWalkCar
BusBikeCarWalkBus
CarBusBikeCarWalk
Example 2. Use the table and frequency bar graph to find the relative frequency for each favorite subject. If a relative-frequency bar graph were drawn, how would its pattern compare with the frequency bar graph?
Subject Math English Science History
Frequency 18 12 15 5

Favorite Subject Bar Graph

Bar graph of favorite subjects with Math 18, English 12, Science 15, and History 5 Favorite Subject Subject Frequency 18 12 15 5 Math English Science History

The tallest bar is Math at 18 students, followed by Science, English, and History.

Example 3. Use the Pareto chart. Identify the greatest and least frequencies, find how many more students chose Drama than Chess, and explain why this is a Pareto chart. If the Drama category combined drama club, musical theatre, and stage crew while each other bar represented only one club, what concern would that create?

Club Signups Pareto Chart

Pareto chart of club signups ordered from Drama 24 to Music 20 to Robotics 11 to Chess 5 After-School Club Signups Club Frequency 24 20 11 5 Drama Music Robotics Chess

The categories are ordered from largest frequency to smallest frequency.

Example 4. Use the pie chart. Identify the most and least popular formats, find the percent who chose either online or hybrid, and verify that the percentages form one whole. A separate graphic lists overlapping reasons for a choice as 63%, 59%, and 52%. Could those percentages be displayed in a pie chart?

Preferred Course Format

Pie chart of preferred course formats with online 40 percent, hybrid 25 percent, evening 20 percent, and weekend 15 percent Preferred Course Format Online 40% Hybrid 25% Evening 20% Weekend 15%

Online is the largest slice at 40 percent, and Weekend is the smallest slice at 15 percent.

Example 5. Choose the most appropriate display. (a) Show the frequency of each eye-color category. (b) Rank customer complaints from most common to least common. (c) Show how a school's annual budget is divided among nonoverlapping categories.
Example 6. Use the side-by-side relative-frequency bar graph. What proportion of the 18-34 group is more likely to buy a product made in the home country? Which age group has the greatest proportion answering More? Describe the apparent pattern as age increases.

Likelihood to Buy When Made in the Home Country

MoreLessNeither Age groupRelative frequency 0.380.540.080.500.410.090.560.350.0918-3435-4445-54

For ages 18 to 34, the relative frequencies are More 0.38, Less 0.54, and Neither 0.08. For ages 35 to 44, they are 0.50, 0.41, and 0.09. For ages 45 to 54, they are 0.56, 0.35, and 0.09.

Example 7. Class 1 has 8 boys and 17 girls. Class 2 has 6 boys and 4 girls. Use the side-by-side frequency and relative-frequency bar graphs to compare the two classes. Which class has the greater frequency and relative frequency for each category? Why is relative frequency the better comparison here?

Class Composition: Counts and Proportions

Class 1 (n = 25)Class 2 (n = 10) Frequency Bar Graph Frequency 86174BoysGirls Relative-Frequency Bar Graph Relative frequency 32%60%68%40%BoysGirls

Class 1 has 8 boys and 17 girls, while Class 2 has 6 boys and 4 girls. The corresponding relative frequencies are 32 percent boys and 68 percent girls in Class 1, and 60 percent boys and 40 percent girls in Class 2.

Section 2.2

Organizing Quantitative Data: The Popular Displays

Read and create grouped frequency displays for quantitative data.

Quick reference

  • Quantitative frequency distributions may use individual values or grouped intervals.
    • For discrete data with relatively few possible values, each value can be its own class.
    • Discrete data with many values and continuous data are usually grouped into nonoverlapping intervals.
    • Frequency is the count in a class. Relative frequency is the class frequency divided by the total frequency.
    • Frequencies should total the sample size \(n\); relative frequencies should total 1, or 100%, except for a small difference caused by rounding.
  • Class terms describe the intervals in a grouped frequency distribution.
    • The lower class limit is the smallest value that can belong to a class; the upper class limit is the largest value that can belong to that class.
    • Class width is the difference between consecutive lower class limits. For the classes 10-19 and 20-29, the width is 20 - 10 = 10, not 19 - 10 = 9.
    • Classes should cover all observations without overlapping. Unless an open-ended class is needed, use equal class widths.
    • If the class setup is not given, begin at the smallest observation or a convenient value below it. To estimate the class width, subtract the minimum from the maximum, divide by the desired number of classes, and round up to a convenient width.
    • Different valid class widths can produce somewhat different-looking summaries. Use enough classes to show the pattern without making the display unnecessarily detailed.
  • A histogram displays a quantitative frequency distribution.
    • Place the classes on the horizontal axis and frequency or relative frequency on the vertical axis.
    • The bars have equal widths and touch because the classes represent adjoining numerical intervals. In a bar graph for qualitative data, the bars are separated.
    • Frequency and relative-frequency histograms for the same classes have the same shape and proportional bar heights, but different vertical scales.
    • A histogram shows how many observations fall in each class, but it usually does not show the exact values within a class.
  • A dot plot displays every observation in a small quantitative data set.
    • Place each possible value on a number line and draw one dot for each observation. Stack repeated observations above the same value.
    • Dot plots preserve individual values, making clusters, gaps, and repeated values easy to see. They become crowded for large data sets.
  • When a question includes several classes, add the relevant frequencies or relative frequencies.
    • At least includes the stated value and all larger values.
    • At most includes the stated value and all smaller values.
  • Describe a quantitative distribution using its overall pattern and the direction of any tail.
    • Symmetric: the left and right sides are approximately mirror images.
    • Bell-shaped: symmetric with one central peak and frequencies that taper in both directions.
    • Uniform: the bar heights are approximately equal.
    • Skewed right: the longer tail points to the right.
    • Skewed left: the longer tail points to the left.
    • Real data may only approximate these shapes, so reasonable judgments can differ. Do not use these shape terms for qualitative data.
  • TI-84 histogram workflow:
    • Enter raw data in L1 using STAT → EDIT.
    • Open 2nd Y= (STAT PLOT), turn Plot1 on, choose the histogram icon, and set Xlist:L1 and Freq:1. Use ZoomStat for an initial window.
    • For specified classes, set Xmin to the first lower class limit and Xscl to the class width.
    • For a grouped table, enter class midpoints in L1, frequencies in L2, and use Freq:L2. StatCrunch is convenient for larger data sets.
Histograms at a Glance
Annotated histogram and four common quantitative distribution shapes

The annotated histogram uses touching bars for the classes 10 through 19, 20 through 29, 30 through 39, 40 through 49, and 50 through 59. The class width is 10 because consecutive lower class limits differ by 10. The first class has lower limit 10 and upper limit 19. Frequency and relative-frequency histograms use the same bar pattern with counts or proportions on the vertical axis. Four smaller labeled histograms show uniform, bell-shaped, skewed-right, and skewed-left distributions.

Example 1. Decide how each quantitative data set should be organized. (a) The number of televisions in a household can be 0, 1, 2, 3, ..., and only a few values occur. (b) Commute time is measured to the nearest tenth of a minute and many different values occur. Identify each variable as discrete or continuous and decide whether individual-value classes or interval classes are more appropriate.
Example 2. Use the grouped frequency table. How many classes are shown? State the lower and upper class limits of the first class, find the class width, find the sample size, and identify the class with the greatest frequency.
Class10-1920-2930-3940-49
Frequency61194
Example 3. The table lists the number of customers waiting on 20 Saturdays. Using the classes 1-3, 4-6, 7-9, 10-12, and 13-15, construct frequency and relative-frequency distributions. Then find the percentage of Saturdays with at least 10 customers and the percentage with at most 6 customers.
Customers waiting
13456
77888
9991010
1112121315
Example 4. The two histograms display the customer data from Example 3. Identify the modal class, compare the shapes and vertical scales, and give a TI-84 setup for creating the histogram from either the raw data or the grouped table.

Frequency Histogram

Customers waitingFrequency0481-34-67-910-1213-15

The class frequencies are 2, 3, 8, 5, and 2.

Relative-Frequency Histogram

Customers waitingRelative frequency00.200.401-34-67-910-1213-15

The class relative frequencies are 0.10, 0.15, 0.40, 0.25, and 0.10.

Example 5. Use the IQ-score histogram. Find the sample size, identify the class with the greatest frequency and the class or classes with the least frequency, and find the percentage of students with scores of at least 110. Can the histogram tell us exactly how many students scored 115?

Student IQ Scores

IQ scoreFrequency0481280-8990-99100-109110-119120-1294101484

The class frequencies from 80 through 129 are 4, 10, 14, 8, and 4.

Example 6. The histograms summarize the same 24 observations using class widths of 5 and 10. Describe the overall shape and explain the tradeoff between the two class widths. Is one class width always correct?

Class Width 5

ValueFrequency0-45-910-1415-1920-2425-29

The six class frequencies are 5, 8, 7, 2, 1, and 1, forming an overall right-skewed pattern.

Class Width 10

ValueFrequency0-910-1920-29

Three class frequencies are 13, 9, and 2.

Example 7. The table shows the number of books read last month by 12 students. Construct a dot plot and identify the most common value.
Books read last month
011222
334456
Section 2.3

Additional Displays of Quantitative Data

Construct and interpret dot plots, stem-and-leaf plots, frequency polygons, ogives, and time-series plots.

Quick reference

  • A dot plot displays each observation as a dot above its value.
    • Repeated values form vertical stacks. Count all dots to find the sample size, and use the tallest stack to identify the value that occurs most often.
    • Dot plots work best for relatively small raw data sets because they preserve individual values.
    • Look for the overall shape, clusters, gaps, and observations separated from the rest of the data.
  • A stem-and-leaf plot organizes quantitative data while preserving the original values.
    • The stem contains the leading digit or digits, and the leaf contains the final digit. A key such as 13 | 5 = 13.5 explains the place value.
    • The same 13 | 5 notation could represent 135, 13.5, or another value under a different place-value setup, so always use the plot's key.
    • Write stems in increasing order, place every leaf with its stem, and order the leaves from least to greatest.
    • Split stems when one row is crowded. Repeat each stem, using the first row for leaves 0-4 and the second row for leaves 5-9.
    • A back-to-back stem-and-leaf plot uses shared stems to compare the distributions of two groups.
  • A frequency polygon displays grouped frequencies using connected points.
    • Find each class midpoint by adding the lower and upper class limits and dividing by 2.
    • Plot each class midpoint on the horizontal axis and its frequency on the vertical axis, then connect consecutive points.
    • Add one midpoint before the first class and one after the last class, each with frequency zero, so the graph meets the horizontal axis.
    • Frequency polygons show the shape of grouped data and can compare multiple distributions on the same axes.
  • Cumulative distributions use running totals.
    • Cumulative frequency is the number of observations at or below a class's upper endpoint.
    • Cumulative relative frequency is the proportion or percentage of observations at or below that endpoint.
    • The final cumulative frequency should equal \(n\), and the final cumulative relative frequency should equal 1, or 100%.
  • An ogive graphs cumulative frequency or cumulative relative frequency.
    • Plot upper class endpoints on the horizontal axis and cumulative values on the vertical axis. Class boundaries may be used when the classes are written with whole-number limits.
    • Begin at zero using the lower boundary before the first class, then connect the points. Because cumulative totals cannot decrease, an ogive must stay level or rise.
    • Use an ogive to find the amount at or below a cutoff, estimate a cutoff for a given cumulative percentage, or find the amount above a cutoff by subtracting the cumulative amount from the total.
  • A time-series plot displays measurements recorded over time.
    • Place time on the horizontal axis and the measured values on the vertical axis, then connect the points chronologically.
    • Describe the overall trend, peaks, lows, changes in direction, and unusual changes.
    • When two series share the same axes, compare their values, trends, and the times when they are closest or farthest apart.
  • Choose the display that matches the data and the question.
    • Use a dot plot for a small raw data set and a stem-and-leaf plot when retaining exact values is especially useful.
    • Use a frequency polygon for grouped frequencies, an ogive for cumulative amounts or cutoff questions, and a time-series plot for values recorded over time.
  • TI-84 workflows for connected statistical plots:
    • For a frequency polygon, enter class midpoints in L1 and frequencies in L2, including the two zero-frequency endpoints. Open 2nd Y=, choose the xyLine plot, and set Xlist:L1 and Ylist:L2.
    • For cumulative totals, enter frequencies in L2 and calculate cumSum(L2)→L3. Use L3/sum(L2)→L4 for cumulative relative frequencies.
    • For an ogive, graph upper class endpoints against L3 or L4 with an xyLine plot. Include the starting point with cumulative value zero.
    • For a time series, enter times in L1 and values in L2, then use an xyLine plot. Turn on a second Stat Plot to compare another series.
    • The TI-84 has no dedicated dot-plot or stem-and-leaf command. Construct those displays by hand or use StatCrunch when the data set is large.
Choosing an Additional Display
Five common quantitative displays and their primary uses

Five labeled panels show a dot plot for small raw data sets, a stem-and-leaf plot for retaining exact values, a frequency polygon for grouped frequencies, an ogive for cumulative amounts, and a time-series plot for values recorded over time.

Example 1. The dot plot shows the one-way commute times of 14 students, rounded to the nearest 5 minutes. Find the sample size and the commute time with the tallest stack. Identify the main cluster, a gap, and a value that may be considered unusual.

Student Commute Times

Minutes510152025303540

Fourteen commute times are shown. Most values are between 10 and 20 minutes, 15 minutes has the tallest stack, no observations occur at 30 or 35 minutes, and one observation occurs at 40 minutes.

Example 2. The stem-and-leaf plot shows the weights, in ounces, of 16 packages. Use the key to reconstruct the original data set. Then state the sample size, minimum weight, and maximum weight.
StemLeaves
135 7 9 9
141 3 6 7 8 9 9
151 4 5
160 2

Key: 13 | 5 represents 13.5 ounces.

Example 3. Construct an ordered stem-and-leaf plot for the data. Then construct a split stem-and-leaf plot, using the first occurrence of each stem for leaves 0-4 and the second for leaves 5-9. Which plot is easier to read, and what is the overall shape?
Delivery time (minutes)
1112131314
1515161718
1921222427
2832364148
Example 4. The back-to-back stem-and-leaf plot compares training completion times, in minutes, for employees assigned to Methods A and B. Which method generally has longer completion times? Identify the stems where the methods overlap and give evidence from the plot.
Method A leavesStemMethod B leaves
9 7 425 8
8 6 3 130 2 4 5 9
7 241 3 6 8
52

Key: 1 | 3 | 0 represents 31 minutes for Method A and 30 minutes for Method B.

Example 5. Use the grouped frequency table to find the class width and all class midpoints. Identify the class with the greatest frequency, then construct a frequency polygon. Include the two zero-frequency endpoints and give a TI-84 setup.
Wait time0-910-1920-2930-3940-49
Frequency26952
Example 6. Use the frequency distribution from Example 5. Complete cumulative frequency and cumulative relative-frequency columns, then list the points for a relative-frequency ogive using class boundaries. What percentage of waits are at most 29 minutes? Which upper class boundary first reaches at least 90%? What percentage are above 19 minutes?
Wait timeFrequencyCumulative frequencyCumulative relative frequency
0-92??
10-196??
20-299??
30-395??
40-492??
Example 7. The table gives annual tutoring-center visits. Construct a time-series plot, identify the highest and lowest years, describe the changing trend, and give a TI-84 setup.
Year2018201920202021202220232024
Visits42485551393437
Example 8. The table and time-series plot compare a region's annual unemployment and inflation rates over 8 years. The misery index is a simple measure of economic strain found by adding the unemployment rate and inflation rate for the same year. A higher index represents a greater combined burden from unemployment and rising prices. Use the table for exact calculations. In which year is the misery index highest, and in which year is it lowest? List each year and its misery-index value.
Rate (%)Year 1Year 2Year 3Year 4Year 5Year 6Year 7Year 8
Unemployment7.58.07.26.55.86.27.06.6
Inflation2.02.53.54.03.02.22.83.4

Unemployment and Inflation Rates

YearPercent123456780246810UnemploymentInflation

The unemployment rate ranges from 5.8 to 8.0 percent and the inflation rate ranges from 2.0 to 4.0 percent over eight years.

Example 9. Choose the most appropriate display for each purpose. (a) Preserve the exact values in a small set of exam scores. (b) Show the grouped frequencies of customer ages and compare the overall shape with another store. (c) Estimate the percentage of scores at or below a cutoff. (d) Show monthly enrollment for the past three years. (e) Display a small raw data set so clusters, gaps, and unusual values are easy to see.
Section 2.4

Graphical Misrepresentations of Data

Identify graphs that distort or exaggerate data.

Quick reference

  • Check the scale before interpreting a graph.
    • Axis values should be clearly labeled and increase by consistent amounts.
    • A truncated vertical axis can exaggerate or hide differences. Bar graphs should generally begin at zero because the length of each bar represents the amount.
    • If a scale is truncated for a valid reason, the break or shortened scale should be clearly shown.
  • Check what each bar or class represents.
    • Bars used to compare categories should have equal visual widths.
    • Percentages or counts from time intervals of different lengths do not provide a fair comparison of how often something occurs.
    • For introductory histograms, use equal class widths unless the graph clearly explains how unequal widths are being handled.
  • Check pictures and visual effects for distortion.
    • If a picture is enlarged in both height and width, its area grows much faster and can exaggerate the difference.
    • Decorative pictures can make it unclear where a bar begins or ends.
    • Three-dimensional graphs can make categories closer to the viewer appear larger. A clear two-dimensional graph is usually easier to compare.
  • Check the labels and context.
    • Use an informative title, clearly labeled axes, units, and enough context to identify the data.
    • Include exact values or a data source when they help the reader judge the display.
  • Decide whether the graph is actually misleading.
    • A graph is not misleading simply because one category is much larger or smaller than another. The display is honest when its lengths, areas, scales, and labels accurately represent the data.
    • To correct a misleading graph, preserve the data while using a clear scale, comparable intervals, simple shapes, and complete labels.
Example 1. The bar graph shows the favorite colors of 28 children. Is it misleading? Explain.

Favorite Colors of 28 Children

Number of childrenFavorite colorGreenBlueRedPurpleYellow0510108532

A horizontal bar graph shows frequencies of 10 for green, 8 for blue, 5 for red, 3 for purple, and 2 for yellow. All bars begin at zero and use the same width.

Example 2. Both graphs show the same median wait times: 50, 52, 54, and 55 minutes. Why is the left graph misleading, and what does the right graph communicate more honestly?

Same Data, Different Vertical Scales

Starts at 48Starts at 0485256MonTueWedThuDayMinutes03060MonTueWedThuDayMinutes

Two bar graphs display wait times of 50, 52, 54, and 55 minutes. The left vertical scale begins at 48, while the right vertical scale begins at zero.

Example 3. A report claims robberies are twice as common from noon to 6 p.m. as from 9 a.m. to noon because the graph shows 24% versus 12%. Why does the graph not support that comparison?

Percent of Robberies by Time Interval

Time intervalPercent of robberies0%12%24%9 a.m.-noonNoon-6 p.m.3 hours6 hours12%24%

A bar graph compares 12 percent of robberies during a three-hour interval with 24 percent during a six-hour interval.

Example 4. A survey graphic uses pencils as bars. Identify two problems with the display and describe a better graph.

Preferred School-Supply Donation

What should the supply drive collect?47%Notebooks33%Folders20%Markers

Three pencil-shaped bars represent 47 percent, 33 percent, and 20 percent. Each pencil includes a rectangular body, an eraser above it, and a pointed tip below it, and the display has no numbered vertical scale.

Example 5. A pictograph doubles both the height and width of a symbol to represent twice as many participants. Why is that misleading?

Pictograph Area Distortion

Same Symbol Scaled Two Ways100 participants200 participantsTwice the height and width

A square for 200 participants is twice as tall and twice as wide as a square for 100 participants, making its area four times as large.

Example 6. Each category represents 25% of the responses. Why can the three-dimensional display still be misleading?

Equal Shares Shown in Three Dimensions

25%25%25%25% All four categories have equal percentages.

A steeply tilted three-dimensional circle graph has four equal 25-percent sections. The two front sections include deep visible side walls, making them appear noticeably larger than the two back sections even though all four values are equal.

Example 7. Use the table to describe a vertical scale that would exaggerate the increase and a scale that would display the increase more honestly.
Year201820192020202120222023
Price per kWh (cents)8.28.48.79.09.29.4

Module 3: Descriptive Statistics

Students compute and interpret center, spread, position, outliers, five-number summaries, and boxplots.

Section 3.1

Measures of Central Tendency

Find and interpret mean, median, and mode.

Quick reference

  • Measures of central tendency describe the center or typical value of a distribution.
    • The mean uses every numerical value. Add the values and divide by the number of observations.
    • For a sample, \(\bar{x}=\frac{\sum x}{n}\). For a population, \(\mu=\frac{\sum x}{N}\).
    • Unless a problem gives another instruction, round the mean to one more decimal place than the original data.
  • The median, \(M\), is the middle of the ordered data.
    • First arrange the values from least to greatest.
    • If \(n\) is odd, the median is the single middle observation.
    • If \(n\) is even, the median is the mean of the two middle observations. The result does not have to be one of the original data values.
  • The mode is the value or category that occurs most often.
    • A data set may have no mode, one mode, two modes (bimodal), or more than two modes (multimodal).
    • The mode can describe qualitative data because categories can be counted even when arithmetic is not meaningful.
    • The TI-84 1-Var Stats screen does not report the mode; inspect the list or a frequency table.
  • A resistant measure is not changed substantially by an extreme value.
    • The median is resistant, but the mean is pulled toward unusually large or small values.
    • For a roughly symmetric distribution without strong outliers, the mean and median are usually close and the mean is commonly reported.
    • For a strongly skewed distribution or one with extreme values, the median usually better represents a typical observation.
    • Skewed left: mean less than median. Roughly symmetric: mean approximately equal to median. Skewed right: mean greater than median.
  • Interpret a measure of center in the context and units of the variable.
    • The word average is sometimes used loosely, so identify whether a report means the mean, median, or mode.
    • Do not calculate a mean for qualitative labels or numerical codes whose arithmetic has no meaning.
  • TI-84 1-Var Stats workflow:
    • Press STAT → 1:Edit and enter the raw data in L1.
    • Press STAT → CALC → 1:1-Var Stats, set List:L1, and choose Calculate.
    • Read \(\bar{x}\) for the sample mean and \(n\) for the number of observations. Scroll down to Med for the median.
Example 1. The number of minutes six students spent completing a quiz were 12, 15, 15, 18, 20, and 22. Find and interpret the mean, median, and mode.
Example 2. Find the mode in each data set. (a) 3, 4, 5, 6. (b) 2, 2, 3, 4, 4. (c) Bus, Walk, Bus, Bike, Walk, Bus.
Example 3. The six ordered values are 7, 12, 21, \(x\), 41, and 49. If the median is 28.5, find \(x\).
Example 4. Fill each blank box with mean, median, or mode. Then describe the skew of each unimodal distribution and compare the three measures using \(\lt\), \(\gt\), or \(\approx\).

Mean, Median, Mode, and Distribution Shape

Negatively skewed(skewed left)Symmetric (no skew)Positively skewed(skewed right)

Three smooth unimodal curves have blank labels beside vertical marker lines. The first curve has a long left tail and three markers from the tail toward the peak. The middle curve is symmetric and has all three markers at its center. The third curve has a long right tail and three markers from the peak toward the tail. Students fill the blanks with mean, median, and mode.

Example 5. Compare the data sets 8, 9, 10, 11 and 8, 9, 10, 11, 52. Find the mean and median of each, then explain what the value 52 demonstrates.
Example 6. The histogram shows amusement-park wait times. Describe the shape and choose the mean or median as the better measure of a typical wait.

Amusement-Park Wait Times

Wait time (minutes)Frequency04812160-45-910-1415-1920-2425-2930-34

The wait-time class frequencies are 16, 12, 8, 6, 4, 3, and 2 from the shortest to the longest class. The tallest bars are in the shortest wait-time classes, and progressively shorter bars extend toward longer wait times.

Example 7. The pulse rates 68, 72, 74, 76, 80, and 86 beats per minute are treated as a population. Find the population mean. Then find the means of Sample A: 68, 72, 74 and Sample B: 76, 80, 86. Does each sample mean under- or overestimate the population mean?
Example 8. A class has 30 exam scores with a mean of 82. The mean of the 29 readable scores is 84. Find the unreadable score.
Example 9. A tornado damage scale uses the category codes 0, 1, 2, 3, 4, and 5. Does it make sense to calculate the mean code? Which measure of center can still be used?
Example 10. Enter 78, 81, 84, 84, 85, and 90 in L1 and run 1-Var Stats. Use the output to identify the mean, median, and sample size. Then identify the mode.
Section 3.2

Measures of Dispersion

Use range, variance, and standard deviation to describe spread.

Quick reference

  • Measures of dispersion describe how spread out the data are.
    • The range is maximum - minimum. It uses only the two extreme values and is not resistant to outliers.
    • Standard deviation measures a typical distance of the observations from the mean. It is reported in the same units as the data.
    • Variance is the square of the standard deviation, so its units are squared.
  • Standard deviation is never negative.
    • A standard deviation of 0 means every observation is equal.
    • A larger standard deviation means more spread when comparing the same variable measured in the same units.
    • A value more than 2 standard deviations from the mean is often considered far from the mean.
  • Use population measures when the data contain the entire population and sample measures when the data are a sample.
    • Population standard deviation is \(\sigma=\sqrt{\frac{\sum(x-\mu)^2}{N}}\), and population variance is \(\sigma^2\).
    • Sample standard deviation is \(s=\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}\), and sample variance is \(s^2\).
    • The formulas show how spread is calculated, but use calculator output for most data sets. A sample standard deviation can be smaller or larger than the population standard deviation.
  • Range and standard deviation are not resistant measures.
    • An extreme value can increase the range immediately and can pull the mean away from the other values, increasing the standard deviation.
    • Compare both the numerical measures and the distribution's shape when describing spread.
  • For a roughly bell-shaped distribution, the Empirical Rule estimates how much data lie near the mean.
    • About 68% lie within 1 standard deviation of the mean, about 95% within 2, and about 99.7% within 3.
    • On either side of the mean, the regions are about 34%, 13.5%, 2.35%, and 0.15% as you move outward.
    • Check that the distribution is roughly bell-shaped before applying the rule.
  • TI-84 1-Var Stats workflow:
    • Enter the data in L1, then choose STAT → CALC → 1:1-Var Stats and calculate using L1.
    • Read Sx for the sample standard deviation and \(\sigma_x\) for the population standard deviation.
    • Square the appropriate standard deviation to obtain the variance.
Empirical Rule for a Bell-Shaped Distribution
Empirical Rule diagram showing percentages within one, two, and three standard deviations of the mean

A bell-shaped curve is divided at the mean and at one, two, and three standard deviations on each side. The center sections contain 34 percent each, the next sections contain 13.5 percent each, the next sections contain 2.35 percent each, and each outer tail contains 0.15 percent. The diagram shows 68 percent within one standard deviation, 95 percent within two, and 99.7 percent within three.

Example 1. The delivery times 6, 8, 10, and 12 minutes are a sample of a restaurant's deliveries. Find the range, sample variance, and sample standard deviation.
Example 2. The same delivery times, 6, 8, 10, and 12 minutes, include every delivery made during a short shift. Find the population variance and population standard deviation.
Example 3. A TI-84 1-Var Stats screen reports the output below for quiz scores from one class. The class is treated as a sample of future students. Report the mean, standard deviation, and variance.
x-bar78.4n25
Sx6.2\(\sigma_x\)6.075
Example 4. Both distributions have a mean near 50. Which distribution has the larger standard deviation? Explain using the histograms.

Same Center, Different Spread

Distribution ADistribution B354147535965203244566880Value

Distribution A is concentrated near 50. Distribution B extends from approximately 20 to 80 and has more observations far from 50.

Example 5. A placement-test distribution has mean 72 and standard deviation 6. A student scores 87. How many standard deviations above the mean is the score, and would it be considered far from the mean?
Example 6. The commute times 18, 20, 21, 22, and 24 minutes have range 6 minutes and sample standard deviation about 2.24 minutes. Replace 24 with 60. What happens to the range and standard deviation? Are either measure resistant?
Example 7. A population has standard deviation 8. Two random samples from it have standard deviations 6.9 and 9.1. Which sample underestimates the population spread, and which overestimates it?
Example 8. Decide whether each statement is possible. (a) A data set has standard deviation -3. (b) A data set has standard deviation 0. (c) Find the sample standard deviation of a sample containing only the value 14.
Example 9. Adult commute times in a city are roughly bell-shaped with mean 30 minutes and standard deviation 5 minutes. Use the Empirical Rule to estimate the percentages with commute times from 25 to 35 minutes, from 20 to 40 minutes, and from 15 to 45 minutes.
Example 10. For the bell-shaped commute-time distribution with mean 30 minutes and standard deviation 5 minutes, estimate each percentage. (a) More than 35 minutes. (b) Less than 20 minutes. (c) From 20 to 35 minutes.
Example 11. A sample of 200 battery lives has mean 10 hours and standard deviation 1 hour. The histogram is strongly skewed right. Should about 190 battery lives be expected between 8 and 12 hours by the Empirical Rule?
Example 12. Treat the 20 values shown as a population. Enter them in L1 and use TI-84 1-Var Stats to find the population mean and population standard deviation. Round each to the nearest whole number. Then find the actual number and percentage of values within 1, 2, and 3 population standard deviations of the mean, and compare the percentages with the Empirical Rule.
Observed values
30353840424446474849
51525354565860626570
Section 3.3

Measures of Central Tendency and Dispersion from Grouped Data

Use frequency tables and grouped data to estimate summary measures.

Quick reference

  • A frequency table summarizes repeated observations.
    • For a table of individual values, treat each value as if it appeared the stated number of times.
    • The total number of observations is the sum of the frequencies: \(n=\sum f\) for a sample or \(N=\sum f\) for a population.
    • The mean is \(\bar{x}=\frac{\sum xf}{\sum f}\) for a sample or \(\mu=\frac{\sum xf}{\sum f}\) for a population.
  • For data grouped into class intervals, use each class midpoint as a representative value.
    • Class midpoint = (lower class limit + upper class limit) / 2.
    • Classes do not need to have equal widths. Find the midpoint of each class separately.
    • Because the original values within each class are unknown, a grouped-data mean, variance, or standard deviation is an approximation. Use raw data when they are available.
  • A weighted mean gives observations different amounts of influence.
    • Use \(\bar{x}_w=\frac{\sum xw}{\sum w}\), where \(x\) is a value and \(w\) is its weight.
    • Common weights include course credit hours, category percentages, quantities purchased, and frequencies.
    • If weights are percentages that total 100%, multiply each value by its decimal weight and add the products.
  • Use the grouped summary in context.
    • Choose Sx and \(s^2\) for sample data; choose \(\sigma_x\) and \(\sigma^2\) for an entire population.
    • Interpret the mean and standard deviation in the original units, and label grouped results as approximate.
    • When comparing groups measured in the same units, compare both center and spread rather than relying on only one statistic.
  • TI-84 grouped-data workflow:
    • Enter the values or class midpoints in L1 and their frequencies or weights in L2.
    • Choose STAT → CALC → 1:1-Var Stats, set List:L1 and FreqList:L2, then calculate.
    • Confirm that the reported \(n\) equals the sum of the frequencies, then read \(\bar{x}\), Sx, or \(\sigma_x\) as required.
Example 1. Use the frequency table to find the mean quiz score and identify the total number of scores.
Score6810
Frequency235
Example 2. The table gives parking fines from a sample of 30 citations. Find each class midpoint, then use 1-Var Stats to approximate the sample mean and sample standard deviation.
Fine$0-$49$50-$99$100-$149$150-$249
Frequency61275
Midpoint24.574.5124.5199.5
Example 3. The grouped distribution contains every employee at a company. A TI-84 output reports \(\bar{x}=42.625\), Sx=13.650, \(\sigma_x=13.564\), and \(n=80\). Report the approximate population mean, population standard deviation, and population variance.
Example 4. The grouped distribution contains every employee at a company. Use the class midpoints and frequencies with TI-84 weighted 1-Var Stats to find the approximate population mean and population standard deviation. Then explain why the Empirical Rule is reasonable and estimate the interval containing about 95% of the ages.
Age20-2930-3940-4950-5960-6970-7980-89
Frequency2614211782

Grouped Employee Ages

20-2930-3940-4950-5960-6970-7980-890510152025Age (years)Frequency

The grouped frequencies 2, 6, 14, 21, 17, 8, and 2 form an approximately symmetric, bell-shaped histogram with one peak at ages 50 through 59.

Example 5. A student earns an A in a 3-credit course, a B in a 4-credit course, a C in a 2-credit course, and a B in a 3-credit course. Using A = 4, B = 3, C = 2, D = 1, and F = 0, find the GPA.
Example 6. A course grade uses homework 15%, quizzes 20%, tests 25%, and the final exam 40%. A student earns 95, 86, 78, and 82 in those categories, respectively. Find the course average.
Example 7. A snack mix contains 2 pounds of nuts at $4.50 per pound, 3 pounds of cereal at $3.20 per pound, and 5 pounds of pretzels at $2.10 per pound. Find the cost per pound of the mixture.
Example 8. Two grouped populations of customer ages have the approximate summaries shown. Compare their centers and spreads.
PopulationApproximate meanApproximate population SD
A40.36 years20.87 years
B41.02 years19.27 years
Section 3.4

Measures of Position and Outliers

Use z-scores, percentiles, quartiles, and outlier fences.

Quick reference

  • A z-score gives a value's distance from the mean in standard-deviation units.
    • Use \(z=\frac{x-\mu}{\sigma}\) for a population or \(z=\frac{x-\bar{x}}{s}\) for a sample.
    • A positive z-score is above the mean, a negative z-score is below the mean, and \(z=0\) is at the mean. A z-score has no units.
    • To recover a raw value, use \(x=\mu+z\sigma\) or \(x=\bar{x}+zs\).
  • Z-scores allow fair relative comparisons between different distributions.
    • When larger values are better, the larger z-score is the stronger relative result.
    • When smaller values are better, such as race times, the more negative z-score is the stronger relative result.
    • After standardizing every value in a population, the z-scores have mean 0 and population standard deviation 1.
  • The kth percentile is a value with about k% of the observations at or below it.
    • The remaining observations are above it. For example, the 80th percentile has about 80% at or below and 20% above.
    • On an ogive, the vertical cumulative relative frequency can be read as a percentile. Read upward from a value to find its percentile or across from a percentile to estimate its value.
  • Quartiles divide ordered data into four parts.
    • \(Q_1\) is the 25th percentile, \(Q_2\) is the median or 50th percentile, and \(Q_3\) is the 75th percentile.
    • About 25% of observations are at or below \(Q_1\), about 50% are at or below \(Q_2\), and about 75% are at or below \(Q_3\).
    • The interquartile range is \(IQR=Q_3-Q_1\). It measures the spread of the middle 50% and is resistant to extreme values.
  • Use the 1.5(IQR) rule to identify potential outliers.
    • Lower fence: \(Q_1-1.5(IQR)\). Upper fence: \(Q_3+1.5(IQR)\).
    • A value below the lower fence or above the upper fence is an outlier. A value equal to a fence is not outside it.
    • An outlier may be a valid unusual observation or may come from measurement, entry, or sampling error. Investigate it rather than automatically deleting it.
  • Choose resistant summaries when the distribution is skewed or has outliers.
    • Median and IQR are resistant; mean, range, and standard deviation are not.
    • For roughly symmetric data without strong outliers, mean and standard deviation are commonly reported. For skewed data or data with outliers, median and IQR usually give a more stable summary.
  • TI-84 quartile workflow:
    • Enter the data in L1 and run 1-Var Stats with List:L1.
    • Scroll down to read minX, \(Q_1\), Med, \(Q_3\), and maxX.
    • The TI-84 reports quartiles but does not label outliers; calculate the fences and compare the original observations with them.
Example 1. Adult men in a city have mean height 69.6 inches with standard deviation 3.2 inches. Adult women have mean height 64.1 inches with standard deviation 3.9 inches. Who is relatively taller: a 75-inch man or a 71-inch woman?
Example 2. Runner A finishes in 52 minutes in a race with mean 60 minutes and standard deviation 4 minutes. Runner B finishes in 44 minutes in a race with mean 50 minutes and standard deviation 2.5 minutes. Which is the more convincing victory relative to that race?
Example 3. A school admits applicants who score at least 2 standard deviations above a test mean of 200 with standard deviation 20. What is the minimum qualifying score?
Example 4. A bolt should be destroyed if its length is more than 4 standard deviations from the mean. Bolt lengths have mean 9.0 cm and standard deviation 0.05 cm. Which lengths should be destroyed?
Example 5. Use the ogive. Interpret the percentile rank of a score of 150, and identify the score at the 25th percentile.

Percentile Ranks of Test Scores

901101301501701900255075100Test scorePercentile

The ogive passes through percentile ranks 0, 10, 25, 60, 85, and 100 at test scores 90, 110, 130, 150, 170, and 190.

Example 6. For the ordered data 12, 14, 15, 17, 19, 20, 21, 24, 27, and 35, find and interpret the quartiles and IQR.
Example 7. A data set has \(Q_1=15\) and \(Q_3=24\). Find the fences and determine whether 1.5, 35, and 49 are outliers.
Example 8. The table gives TI-84 quartile output for delivery times in two regions. Which region has the more dispersed middle 50%?
RegionQ1MedianQ3
A182538
B202631
Example 9. The data 20, 22, 24, 25, 26, 28, 30, 32, 34, and 100 contain an extreme value. If 100 is changed to 200, what happens to the standard deviation and IQR? What property does this illustrate?
Section 3.5

The Five-Number Summary and Boxplots

Summarize data with quartiles, IQR, outliers, and boxplots.

Quick reference

  • The five-number summary lists minimum, \(Q_1\), median, \(Q_3\), and maximum in ascending order.
    • Use ordered data or the lower portion of TI-84 1-Var Stats output to find the five values.
    • The five-number summary describes position but does not show every observation, the mean, or the standard deviation.
  • A modified boxplot displays quartiles, non-outlier extremes, and outliers on a number line.
    • The box runs from \(Q_1\) to \(Q_3\), so its length represents the IQR. The line inside the box marks the median.
    • Whiskers extend to the smallest and largest observations that are not outliers; they do not extend to the fences unless an observation occurs there.
    • Plot observations outside the 1.5(IQR) fences separately.
  • To construct a modified boxplot:
    • Find \(Q_1\), the median, \(Q_3\), the IQR, and both outlier fences.
    • Draw a scaled number line, make the box from \(Q_1\) to \(Q_3\), and mark the median inside it.
    • Draw whiskers to the most extreme non-outliers and plot each outlier separately.
  • A boxplot gives clues about distribution shape.
    • Roughly symmetric: the median is near the center of the box and the whiskers have similar lengths.
    • Skewed right: the median is usually left of the box's center and the right side or right whisker is longer.
    • Skewed left: the median is usually right of the box's center and the left side or left whisker is longer. Treat these as visual clues rather than absolute rules.
  • Use side-by-side boxplots to compare groups on the same scale.
    • Compare medians for center, IQRs and overall ranges for spread, and separately plotted points for outliers.
    • A group with a smaller IQR or range is more consistent. A longer box and whiskers usually suggest greater spread, but a boxplot does not give an exact standard deviation.
    • A boxplot does not show clusters, gaps, or sample size, so use the available evidence without claiming more than the display supports.
  • TI-84 modified-boxplot workflow:
    • Enter the data in a list. Open 2nd → Y= (STAT PLOT), turn one plot on, and choose the modified boxplot icon with separate outlier marks.
    • Set Xlist to the data list and Freq to 1, then use ZOOM → 9:ZoomStat.
    • Press TRACE and move left or right to read the quartiles, whisker endpoints, and outliers.
Anatomy of a Modified Boxplot
Labeled anatomy of a modified boxplot

A modified boxplot labels the smallest non-outlier, first quartile, median, third quartile, largest non-outlier, and a separately plotted outlier. The box from Q1 to Q3 represents the middle 50 percent and has length equal to the IQR.

Example 1. Find the five-number summary for \(2,4,5,8,10,12,15\).
Example 2. Use the modified boxplot to identify and interpret the smallest non-outlier, \(Q_1\), median, \(Q_3\), largest non-outlier, and outlier. Find the IQR and state what the box represents.

Modified Boxplot

Modified boxplot with smallest non-outlier 12, first quartile 18, median 24, third quartile 31, largest non-outlier 38, and outlier 52 Quiz Scores 1020304050 Smallestnon-outlier12 Q118 Median24 Q331 Largestnon-outlier38 Outlier52

The smallest non-outlier is 12, Q1 is 18, the median is 24, Q3 is 31, the largest non-outlier is 38, and the outlier 52 is plotted separately.

Example 3. An exam has five-number summary 61, 68, 77, 89, 97 and no outliers. Construct its boxplot on a scaled number line.
Example 4. Use the side-by-side boxplots to compare typical delivery time, consistency, shape, and outliers for Routes A and B.

Delivery Times by Route

1030507090Route ARoute B88Delivery time (minutes)

Route A has quartiles 24, 30, and 36 minutes and is roughly symmetric. Route B has quartiles 24, 42, and 44 minutes, a long right whisker, and an outlier at 88 minutes.

Example 5. Boxplot I spans approximately 5 to 18 with an IQR of 6. Boxplot II spans approximately 1 to 29 with an IQR of 16. Which data set likely has the larger standard deviation? Can the exact standard deviations be found from the boxplots?
Example 6. A student enters tablet weights in L1. Give the TI-84 steps to display a modified boxplot and inspect its values.

Module 4: Correlation and Regression

Students describe relationships between two quantitative variables and use linear regression carefully.

Section 4.1

Scatter Diagrams and Correlation

Describe scatterplots and interpret the correlation coefficient.

Quick reference

  • A scatterplot displays paired quantitative data measured on the same individuals or objects.
    • Plot the explanatory or predictor variable on the horizontal axis and the response variable on the vertical axis.
    • The explanatory variable may help explain or predict the response, but the roles are not always determined by the data alone. Use the study's question and context.
  • Describe a scatterplot by direction, form, strength, and unusual features.
    • Direction may be positive, negative, or neither. Form may be linear, curved, or show no clear pattern.
    • Strength describes how closely the points follow the form. Also note clusters, gaps, and points that do not follow the overall pattern.
    • Always inspect the scatterplot. A numerical summary alone can hide curvature or an influential unusual point.
  • The linear correlation coefficient measures the direction and strength of a linear relationship.
    • Use \(r\) for a sample and \(\rho\) for a population. The long formula is \(r=\frac{1}{n-1}\sum\left(\frac{x-\bar{x}}{s_x}\right)\left(\frac{y-\bar{y}}{s_y}\right)\), but technology is used for computation.
    • The value is between -1 and 1. The sign gives direction; the closer \(|r|\) is to 1, the stronger the linear relationship.
    • A value near 0 means little evidence of a linear relationship; a strong curved relationship can still have \(r\) near 0.
  • Correlation is unitless and is not resistant.
    • Changing inches to centimeters or applying another positive linear unit conversion does not change \(r\).
    • An unusual point can change the direction or strength of \(r\), so investigate it with the scatterplot.
  • Use the homework critical-value table to decide whether the sample shows a linear relation.
    • Find \(|r|\) and the critical value for the sample size \(n\).
    • If \(|r|\) is greater than the critical value, conclude that a linear relation exists; use the sign of \(r\) to call it positive or negative.
    • If \(|r|\) is not greater than the critical value, conclude that the data do not provide evidence of a linear relation.
  • Correlation does not by itself establish causation.
    • With observational data, say the variables are associated, not that one causes the other.
    • A lurking variable may be related to both variables and may help explain the observed association.
  • TI-84 scatterplot and correlation workflow:
    • Enter explanatory values in L1 and matching response values in L2. Keep each pair in the same row.
    • Use STAT PLOT to turn on a scatterplot with Xlist:L1 and Ylist:L2, then use ZoomStat.
    • Run LinReg(ax+b) to read \(r\). In this form, \(a\) is the slope and \(b\) is the intercept. If \(r\) is hidden, run DiagnosticOn from the calculator's catalog first.
Example 1. Use the scatterplot. Describe the direction, form, and strength of the association.

Scatterplot: Study Time and Score

Scatterplot with points rising from left to right in a strong positive linear pattern Study Time and Exam Score Study time (hours) Exam score

The points rise from left to right and stay close to a line.

Example 2. Which correlation is stronger: \(r=-0.91\) or \(r=0.45\)?
Example 3. Can \(r=1.24\) be a correlation coefficient?
Example 4. A study finds a strong correlation between ice cream sales and drowning incidents. What causal wording should be avoided?
Example 5. A researcher wants to use commute time to predict a well-being score. Identify the explanatory and response variables. Then use the paired table and TI-84 output to describe the relationship.
Commute time (min)520356085
Well-being score69.167.465.663.060.5
Example 6. For \(n=8\) paired observations, a TI-84 gives \(r=0.682\). The homework critical value for \(n=8\) is 0.707. Is there evidence of a linear relation?
Example 7. Heights and head circumferences measured in inches have \(r=0.955\). What happens to \(r\) if both variables are converted to centimeters?
Example 8. Both data sets have nearly the same correlation, \(r\approx-0.82\). Why is the correlation coefficient alone not an adequate summary?

Similar Correlations, Different Patterns

Data Set AData Set B

Data Set A has a downward linear cloud. Data Set B has a curved pattern and a far-right low point even though its correlation is similar.

Example 9. Predict the likely correlation direction for each pair. (a) Number of dinner guests and total dinner bill. (b) Day of the week and outdoor temperature. (c) Outdoor temperature and number of people wearing coats.
Section 4.2

Least-Squares Regression

Use regression equations for prediction and interpret slope, intercept, residuals, and extrapolation.

Quick reference

  • The least-squares regression line predicts a quantitative response from a quantitative explanatory variable.
    • Write the line as \(\hat{y}=b_0+b_1x\), where \(\hat{y}\) is the predicted response.
    • The line minimizes the sum of the squared vertical residuals. For formula context, \(b_1=r\frac{s_y}{s_x}\) and \(b_0=\bar{y}-b_1\bar{x}\), but use technology to fit the model.
    • Fit and use a linear model only after the scatterplot and correlation support a linear relationship.
  • Interpret the slope and intercept in context.
    • The slope is the predicted change in the response for each one-unit increase in the explanatory variable, on average. Include both variables and their units.
    • The intercept is the predicted response when \(x=0\). Interpret it only when zero is meaningful and reasonably within the scope of the data.
    • A negative slope predicts a decrease in \(y\) as \(x\) increases; a positive slope predicts an increase.
  • Use the regression equation for prediction and comparison.
    • Substitute an explanatory value for \(x\) to find the predicted response \(\hat{y}\). The same prediction can estimate a mean response at that \(x\) or an individual response, though individual values vary around the line.
    • A residual is observed - predicted: \(e=y-\hat{y}\). A positive residual means the observation is above the line; a negative residual means it is below the line.
    • Keep more digits in the regression equation during calculations, then round the final prediction as requested.
  • Limit predictions to the model's scope.
    • Interpolation predicts within the observed range of \(x\); extrapolation predicts outside it and may be unreliable because the pattern may change.
    • Do not automatically apply a model to a different population or type of subject, even when the new \(x\)-value lies in the numerical range.
  • The coefficient of determination measures explained variation.
    • For simple linear regression, \(R^2=r^2\). Convert it to a percent for interpretation.
    • Say: 'R-squared percent of the variation in the response is explained by the linear model with the explanatory variable.' Do not say that percent of the response itself is explained.
  • Use a residual plot to check whether a linear model is appropriate.
    • A useful linear model has residuals scattered around zero without a clear pattern and with reasonably similar vertical spread across \(x\).
    • A curved pattern suggests a nonlinear relationship. A fan shape suggests changing residual variation. A point far above or below the others may be an outlier.
  • TI-84 regression workflow:
    • Enter explanatory values in L1 and paired responses in L2. Turn on DiagnosticOn when \(r\) and \(r^2\) are needed.
    • Run LinReg(ax+b) using L1,L2. This course uses that form consistently, so \(a\) is the slope and \(b\) is the intercept.
    • The TI-84 also lists LinReg(a+bx), which reverses the coefficient roles: \(a\) is the intercept and \(b\) is the slope. Check the displayed equation form before interpreting output from another source.
    • To graph the fitted line, store the regression equation to Y1, turn on the scatterplot, and use ZoomStat.
Example 1. Use the regression graph. Interpret the slope in context.

Least-Squares Regression Line

Scatterplot with a least-squares regression line through positively associated points Predicted Score from Study Time Å· = 4.8x + 52.4

The line models the upward linear trend in the paired data.

Example 2. The TI-84 LinReg(ax+b) output gives \(a=4.8\), \(b=52.4\), \(r=0.94\), and \(r^2=0.884\) for predicting exam score from study time in hours. Write the regression equation and interpret each output value.
Example 3. Use the residual plot. Does the residual plot show an obvious curved pattern?

Residual Plot

Residual plot with points scattered around the zero residual line Residuals from a Linear Model Explanatory variable Residual 0

Residuals are scattered around zero without a clear curve, which supports a linear model.

Example 4. Data were collected for \(x\)-values from \(2\) to \(15\). Is predicting at \(x=40\) interpolation or extrapolation?
Example 5. A commute-time model is \(\hat{y}=69.051-0.095x\), where \(x\) is commute time in minutes and \(y\) is a well-being score. Interpret the slope, predict the score for a 25-minute commute, and find the residual if the observed score is 66.0.
Example 6. For regions with 15% to 60% of adults holding a bachelor's degree, the model is \(\hat{y}=17884+622.2x\), where \(x\) is the percentage of adults holding a bachelor's degree and \(\hat{y}\) is the predicted median income in dollars. Interpret the slope. Should the intercept be interpreted?
Example 7. A regression model was built from gas-powered cars. A hybrid car's weight falls within the observed weight range. Is the model automatically appropriate for predicting the hybrid's city mileage?
Example 8. The scatterplot appears strongly associated and has \(r=-0.97\), but the residual plot has a clear curved pattern. Is the linear model appropriate?

Residual Plot with Curvature

Explanatory variableResidual0

Residuals form a U-shaped pattern: positive at low and high explanatory values and negative in the middle.

Module 5: Probability

Students compute probabilities using complements, addition rules, multiplication rules, conditional probability, and counting techniques.

Section 5.1

Probability Rules

Use basic probability language and simple probability rules.

Quick reference

  • Probability measures the likelihood of an outcome or event.
    • A probability experiment is a repeatable process with uncertain results. An outcome is one possible result, the sample space is the collection of all possible outcomes, and an event contains one or more outcomes.
    • Probabilities are between 0 and 1 inclusive. Probability 0 represents an impossible event, and probability 1 represents a certain event.
    • An event is often called unusual when \(P(E)\le0.05\), meaning its probability is 0.05 or less, unless the problem sets another cutoff.
  • A probability model lists each outcome and its probability.
    • Every probability must be between 0 and 1 inclusive, and all probabilities must sum to 1.
    • When outcomes are equally likely, \(P(E)=\frac{\text{number of outcomes in }E}{\text{number of outcomes in the sample space}}\).
  • Probability can come from different sources.
    • Theoretical probability uses a known model with equally likely outcomes, such as a fair die.
    • Empirical probability uses observed relative frequency: number of times the event occurred / number of trials.
    • Subjective probability is an informed judgment based on experience or available information rather than equally likely outcomes or repeated data.
  • Long-run relative frequency tends to settle near the true probability as the number of trials grows.
    • Short runs can vary substantially, so an empirical result does not need to match a theoretical probability exactly.
    • When a theoretical probability is known, compare it with the empirical probability. A difference may be random variation and does not by itself prove that the model is wrong; more trials provide stronger evidence.
    • A probability can be used to predict an approximate long-run count: expected count = number of trials x probability.
  • The complement of event \(A\), written \(A^c\), contains all outcomes where \(A\) does not occur.
    • Complement rule: \(P(A^c)=1-P(A)\).
    • The event and its complement are mutually exclusive and together cover the entire sample space.
Example 1. If \(P(A)=0.37\), find \(P(A^c)\).
Example 2. Can a probability equal \(1.08\)?
Example 3. A fair die is rolled. What is the sample space?
Example 4. A fair die is rolled. Find the probability of rolling an even number.
Example 5. Use the Venn diagram. How many students are in neither Art nor Band?

Two-Event Venn Diagram

Venn diagram with event A count 18 only, event B count 12 only, overlap count 10, and outside count 20 Club Survey: Art and Band A: Art B: Band 18 10 12 20

The overlap belongs to both events and must not be counted twice.

Example 6. A coin is tossed 100 times and lands tails 36 times. (a) Find the empirical probability of tails. (b) If the coin is fair, state the theoretical probability of tails. (c) Compare the results. Does this experiment prove that the coin is unfair?
Example 7. Does the table define a probability model? If not, explain why.
ColorRedBlueGreenYellow
Probability0.250.400.300.15
Example 8. Classify each probability. (a) A fair die has probability 1/6 of landing on 4. (b) In 400 rolls, a die landed on 4 a total of 94 times. (c) A meteorologist judges a 30% chance of rain using current conditions and experience.
Example 9. A type of theft has probability 0.010. Is it unusual using the 0.05 guideline? In 2,000 similar records, about how many such thefts would be expected?
Example 10. A person draws one playing card and records its suit, then spins a three-space spinner labeled 1, 2, and 3. Use C, D, H, and S for the card suits. List the sample space.
Section 5.2

The Addition Rule and Complements

Compute probabilities involving "or" statements.

Quick reference

  • The union \(A\text{ or }B\) contains outcomes in \(A\), in \(B\), or in both.
    • In probability, or is inclusive unless the wording explicitly says exactly one.
    • The intersection \(A\text{ and }B\) contains outcomes shared by both events.
  • Mutually exclusive or disjoint events cannot happen together.
    • For disjoint events, \(P(A\text{ and }B)=0\), so \(P(A\text{ or }B)=P(A)+P(B)\).
    • Do not assume events are disjoint merely because their labels differ; decide whether one outcome can belong to both.
  • Use the general addition rule whenever events may overlap.
    • \(P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B)\).
    • Subtract the overlap once because it was included in both individual probabilities. The same idea appears visually in a Venn diagram.
  • Use the complement rule for not, none, or neither.
    • \(P(A^c)=1-P(A)\).
    • For neither \(A\) nor \(B\), find the complement of \(A\text{ or }B\): \(1-P(A\text{ or }B)\).
  • Use the structure of a standard 52-card deck when card events appear.
    • The deck has four suits with 13 cards in each suit. Hearts and diamonds are red; clubs and spades are black.
    • Each rank appears four times, once in each suit. There are four aces, four twos, and so on, including four jacks, four queens, and four kings.
    • Events involving different ranks are disjoint for one draw, but a rank and a suit overlap in one card, such as the six of diamonds.
  • Read a two-way table by identifying the correct cells and the grand total.
    • For an and event, use the single intersection cell. For an or event, combine the relevant row and column without double-counting their shared cell.
    • For an unconditional probability, divide the desired count by the table's grand total. Conditional probabilities use a restricted denominator and are covered in Section 5.4.
Example 1. If \(P(A)=0.30\), \(P(B)=0.25\), and \(A\) and \(B\) are mutually exclusive, find \(P(A\text{ or }B)\).
Example 2. If \(P(A)=0.40\), \(P(B)=0.35\), and \(P(A\text{ and }B)=0.10\), find \(P(A\text{ or }B)\).
Example 3. Use the Venn diagram. (a) How many students were surveyed? (b) How many participate only in Sports? (c) Find \(P(S\text{ and }M)\). (d) Find \(P(S\text{ or }M)\). (e) Find the probability of neither activity. (f) Are Sports and Music mutually exclusive?

Reading Every Region of a Venn Diagram

Venn diagram with Sports-only count 14, Music-only count 10, overlap count 8, and outside count 6 School Activities: Sports and Music S: Sports M: Music 14 8 10 6

Fourteen students are in Sports only, eight are in both Sports and Music, ten are in Music only, and six are in neither activity.

Example 4. If the probability of at least one success is needed, what complement is often easier?
Example 5. Use the two-way table to find the probability that a randomly selected adult is age 45-54 or uses social media.
Social media18-3435-4445-5455+Total
Uses117868347333
Does not use30335665184
Total147119139112517
Example 6. One card is drawn from a standard 52-card deck. Find each probability. (a) An ace or a ten. (b) An ace, a ten, or an eight. (c) A six or a diamond.
Example 7. If \(P(A\text{ or }B)=0.64\), find the probability of neither \(A\) nor \(B\).
Example 8. A fair die is rolled once. Let \(A=\{2,4,6\}\) be the event of rolling an even number and \(B=\{4,5,6\}\) be the event of rolling a number greater than 3. List the outcomes in \(A\text{ or }B\), \(A\text{ and }B\), and \(A^c\).
Section 5.3

Independence and the Multiplication Rule

Use multiplication rules for independent and dependent events.

Quick reference

  • Independent events do not change each other's probabilities; dependent events do.
    • Use the multiplication check: the events are independent when \(P(A\text{ and }B)=P(A)P(B)\).
    • Independence is an assumption that must fit the context. Repeated real-world outcomes are not automatically independent.
  • Mutually exclusive and independent do not mean the same thing.
    • To check mutual exclusivity, ask: Can both events happen in the same trial? If not, they are mutually exclusive.
    • To check independence, ask: Does knowing that one event occurred change the probability of the other? If not, they are independent; if it does, they are dependent.
    • Mutually exclusive events with positive probabilities are dependent. Once one occurs, the probability of the other becomes 0.
    • Mutually exclusive events can also be independent only in the special case where at least one event has probability 0.
  • For independent events, multiply probabilities to find an and probability.
    • \(P(A\text{ and }B)=P(A)P(B)\). For repeated independent trials with the same probability \(p\), the probability of success every time is \(p^n\).
    • Interpret a small probability as a long-run frequency when requested: expected repetitions = number of repetitions x probability.
  • With replacement usually keeps selections independent; without replacement usually makes them dependent.
    • With replacement, restore the selected item before the next draw, so both the numerator and denominator return to their original values.
    • Without replacement, update the remaining favorable items and total items after each draw. A tree diagram helps display the changing branches.
  • Use a complement for at least one.
    • \(P(\text{at least one})=1-P(\text{none})\).
    • For independent trials, multiply the failure probabilities to find none, then subtract from 1.
Example 1. A coin is flipped twice. Find the probability of two heads.
Example 2. Use the tree diagram. A bag has \(5\) red and \(7\) blue marbles. Two marbles are drawn without replacement. Find the probability both are red.

Without-Replacement Tree Diagram

Tree diagram for two marble draws without replacement from 5 red and 7 blue marbles Two Draws Without Replacement RedBlue RedBlue RedBlue 5/127/12 4/117/11 5/116/11

After the first draw, the second-draw probabilities change because the marble is not replaced.

Example 3. Use the comparison table. Why does drawing without replacement usually create dependent events?
Setting First red Second red after first red Are draws independent?
With replacement 5/12 5/12 Yes
Without replacement 5/12 4/11 No
Example 4. Are two rolls of a fair die independent?
Example 5. A fair coin is flipped five times. Find and interpret the probability of five tails.
Example 6. A screening test correctly returns positive for an affected person with probability 0.80. For five independent affected people, find the probability that all five tests are positive and the probability that at least one is negative.
Example 7. Are the events 'a randomly selected student is a senior' and 'the student is a sophomore' mutually exclusive? Are they independent?
Example 8. Use the multiplication check to determine whether the events are independent. In both cases, \(P(A)=0.40\) and \(P(B)=0.25\). (a) \(P(A\text{ and }B)=0.10\). (b) \(P(A\text{ and }B)=0.16\).
Example 9. One card is drawn from a standard 52-card deck. For each pair of events, determine whether the events are mutually exclusive or not mutually exclusive and whether they are independent or dependent. Support each classification using outcomes or probabilities. (a) Event A: Draw a heart. Event B: Draw a spade. (b) Event A: Draw a heart. Event B: Draw a face card. (c) Event A: Draw a heart. Event B: Draw a red card. (d) Event A: Draw a joker. Event B: Draw a heart.
Example 10. One standard die is rolled. For each pair of events, determine whether the events are mutually exclusive or not mutually exclusive and whether they are independent or dependent. Support each classification using outcomes or probabilities. (a) Event A: Roll a 1. Event B: Roll an even number. (b) Event A: Roll an even number. Event B: Roll a number greater than 2. (c) Event A: Roll an even number. Event B: Roll a number less than 4. (d) Event A: Roll a 7. Event B: Roll an even number.
Section 5.4

Conditional Probability and the General Multiplication Rule

Compute and interpret conditional probabilities.

Quick reference

  • Conditional probability restricts the sample space to known information.
    • \(P(A\mid B)\) means the probability of \(A\) given that \(B\) has occurred.
    • Use \(P(A\mid B)=\frac{P(A\text{ and }B)}{P(B)}\) or, with counts, number in both \(A\) and \(B\) / number in \(B\).
    • The event after the vertical bar supplies the denominator.
  • The order in conditional notation matters.
    • \(P(A\mid B)\) and \(P(B\mid A)\) usually have different restricted sample spaces and different denominators.
    • Translate the condition into words before selecting numbers from a table.
  • In a two-way table, condition on a row or column total.
    • Locate the row or column named after given. Its total is the denominator.
    • The numerator is the intersection cell that also satisfies the event before the vertical bar.
  • The general multiplication rule works for independent or dependent events.
    • \(P(A\text{ and }B)=P(A)P(B\mid A)=P(B)P(A\mid B)\).
    • For independent events, the conditional probability equals the original probability, reducing the rule to \(P(A)P(B)\).
    • With replacement or replay allowed, the original probabilities return before the next selection. Without replacement, multiply along the desired path while updating the favorable count and total after every selection.
  • Use addition when an event can occur through more than one disjoint path.
    • For exactly one of two types, calculate first type then second plus second type then first.
    • For one red and one yellow without replacement, add \(P(R\text{ then }Y)+P(Y\text{ then }R)\).
  • Check independence by comparing conditional and unconditional probabilities.
    • For independent events, \(P(A\mid B)=P(A)\) whenever \(P(B)>0\). This is equivalent to \(P(A\text{ and }B)=P(A)P(B)\).
    • Compare the overall rate for an event with the rate inside the given group. These are \(P(A)\) and \(P(A\mid B)\).
    • If the rates are the same, allowing for normal rounding differences, the events are independent. If knowing the group changes the rate meaningfully, the events are dependent.
Example 1. If \(P(A\text{ and }B)=0.18\) and \(P(B)=0.30\), find \(P(A\mid B)\).
Example 2. Use the two-way table. Find the probability a student takes biology given they take statistics.
Student group Biology Not biology Total
Statistics 18 12 30
Not statistics 14 36 50
Total 32 48 80
Example 3. Does \(P(A\mid B)\) always equal \(P(B\mid A)\)?
Example 4. If \(P(B)=0.40\) and \(P(A\mid B)=0.25\), find \(P(A\text{ and }B)\).
Example 5. Using the enrollment table from Example 2, find \(P(\text{Statistics}\mid\text{Biology})\). Explain why it differs from \(P(\text{Biology}\mid\text{Statistics})\).
Example 6. A bag has 11 red, 10 yellow, and 9 purple bulbs. Two bulbs are drawn without replacement. Find the probability that the first is red and the second is yellow.
Example 7. Using the same bulb bag, find the probability that exactly one bulb is red and the other is yellow.
Example 8. In a survey of adults, \(P(\text{uses social media})=0.644\) and \(P(\text{uses social media}\mid\text{age 35-44})=0.723\). Use the conditional-probability test to determine whether social-media use and being age 35-44 are independent.
Example 9. A Spotify playlist has 15 tracks, and you like 2 of them. The playlist first plays every track once in random order. For the first two tracks, find the probability that (a) you like both, (b) you like neither, and (c) you like exactly one. Is liking both unusual using the 0.05 guideline? Then repeat (a)-(c) if replay is allowed before all 15 tracks have played.
Example 10. A five-card flush consists of five cards from the same suit. (a) Find the probability of five diamonds. (b) Find the probability of a flush in any of the four suits. (c) A royal flush is the ten, jack, queen, king, and ace of one suit. Find the probability of a royal flush.
Section 5.5

Counting Techniques

Use the fundamental counting principle, permutations, and combinations.

Quick reference

  • The Fundamental Counting Principle multiplies the number of choices across successive stages.
    • If one stage has \(a\) choices and the next has \(b\), there are \(ab\) ordered outcomes.
    • When repetition is allowed, the same choice count may be reused at each stage, such as \(5^7\) seven-digit keypad codes using five keys.
  • A factorial counts arrangements of distinct objects.
    • \(n!=n(n-1)(n-2)\cdots1\), and \(0!=1\).
    • Arranging all \(n\) distinct objects uses \(n!\).
  • Use a permutation when order or assigned roles matter.
    • \({}_nP_r=\frac{n!}{(n-r)!}\) counts ordered selections of \(r\) distinct objects from \(n\).
    • Examples include race finishes, officer positions, and ordered playlists without repetition.
  • Use a combination when only the selected group matters.
    • \({}_nC_r=\frac{n!}{r!(n-r)!}\) counts unordered selections of \(r\) objects from \(n\).
    • Examples include committees, card hands, lottery selections, and simple random samples.
  • For arrangements with identical repeated objects, divide out duplicate orders.
    • If \(n\) objects include repeated groups of sizes \(n_1,n_2,\ldots\), the number of distinguishable arrangements is \(\frac{n!}{n_1!n_2!\cdots}\).
    • Use this for repeated letters, repeated tree types, or birth-order categories with fixed counts.
  • Counting can supply the numerator and denominator of a probability.
    • For equally likely outcomes, \(P(E)=\frac{\text{favorable outcomes}}{\text{total outcomes}}\). Count both with methods that match the selection rules.
    • When selecting without replacement from two groups, count a specific composition by multiplying combinations. For example, choose the desired number of liked tracks and the remaining number of unliked tracks, then divide by the number of all possible selections.
    • On a TI-84, enter \(n\), press MATH → PRB, select nPr or nCr, enter \(r\), and press ENTER. Factorial is in the same menu.
Example 1. A code uses \(3\) letters followed by \(2\) digits. If repetition is allowed, how many codes are possible?
Example 2. How many ways can \(4\) students be arranged in a line from a group of \(10\)?
Example 3. How many committees of \(4\) can be chosen from \(10\) students?
Example 4. Should order matter when choosing a committee?
Example 5. Evaluate \(8!\), \({}_{13}P_0\), and \({}_{8}C_8\).
Example 6. A race has 39 cars. In how many ways can first, second, and third place be awarded? Which TI-84 command applies?
Example 7. How many distinguishable arrangements can be made from the letters in BALLOON?
Example 8. A shipment has 20 components, 3 defective and 17 good. Four components are selected without replacement. Find the probability that the shipment is rejected if at least one selected component is defective.
Example 9. A Spotify playlist has 17 tracks, and you like 6 of them. Each track plays once in random order. Among the first 5 tracks, find the probability that you like (a) exactly 2, (b) exactly 3, and (c) all 5.
Example 10. A player is dealt a five-card hand from a standard 52-card deck. Find the probability of receiving exactly four cards of one rank.

Module 6: Discrete Random Variables and Binomial Distributions

Students work with discrete probability distributions, expected value, and binomial probabilities.

Section 6.1

Discrete Random Variables

Determine whether a distribution is valid and compute expected values.

Quick reference

  • A random variable assigns a numerical value to each outcome of a probability experiment.
    • A discrete random variable has a finite or countable set of possible values, often counts such as 0, 1, 2, and so on.
    • A continuous random variable can take any value in an interval, often measurements such as time, weight, area, or distance.
    • State realistic possible values when classifying a variable; counts use whole numbers, while measurements may include decimals.
  • A discrete probability distribution lists each possible value and its probability.
    • Every probability must satisfy \(0\le P(x)\le1\), and \(\sum P(x)=1\).
    • To find a missing probability, subtract the sum of the known probabilities from 1.
    • A probability histogram uses separated bars because the random variable takes discrete values.
  • Expected value is the probability-weighted long-run mean.
    • \(\mu_X=E(X)=\sum xP(x)\). Multiply each value by its probability and add the products.
    • Interpret expected value as an average over many repetitions, not as a prediction for one trial. It does not need to be a possible individual outcome.
    • For games, insurance, or investments, a positive expected value is an average gain and a negative expected value is an average loss from the stated point of view.
    • Distinguish a payout or prize from net gain. Subtract the cost to play when the listed values are payouts, but do not subtract it again when the problem already gives net gains and losses.
  • The standard deviation describes the typical distance of outcomes from the expected value.
    • For formula context, \(\sigma_X=\sqrt{\sum (x-\mu_X)^2P(x)}\).
    • Report the standard deviation in the same units as the random variable. A larger value means more variable outcomes.
  • TI-84 weighted-statistics workflow:
    • Enter possible values in L1 and probabilities in L2.
    • Run 1-Var Stats with List:L1 and FreqList:L2.
    • Read \(\bar{x}\) as the expected value and \(\sigma_x\) as the distribution's standard deviation. The displayed \(n\) may equal 1 when probabilities are used as weights; it is not the number of trials.
Example 1. Is this a valid probability distribution?
\(x\) 0 1 2 3
\(P(x)\) 0.20 0.35 0.25 0.20
Example 2. Find the expected value for \(x=0,1,2\) with probabilities \(0.2,0.5,0.3\).
Example 3. A probability table sums to \(1.08\). Is it valid?
Example 4. Classify each random variable and state its possible values. (a) Number of website visits in a day. (b) Time needed to download a file.
Example 5. Find the missing probability and verify the distribution.
x0123
P(x)0.180.420.27?
Example 6. A $10 game pays a net gain of $340 with probability 1/38 and a net loss of $10 otherwise. Find and interpret the expected value.
Example 7. The table gives the cash-prize distribution for a $1 lottery ticket. Find and interpret the expected cash prize. Then find and interpret the expected profit from one ticket.
Cash prize, xP(x)
$13,000,0000.00000000699
$200,0000.00000015
$10,0000.000001655
$1000.000172835
$70.004331105
$40.006950843
$30.01357866
$00.97496474501
Example 8. An insurance company sells a $220,000 one-year term life insurance policy for a $190 premium. The probability that the insured person survives the year is 0.999544. Determine the company's value if the insured person survives and if the insured person dies. Then find and interpret the expected value of the policy to the insurance company.
Example 9. The table gives the probability distribution for the number of urgent service calls received in one hour. Verify the distribution, construct its probability histogram, then use TI-84 weighted 1-Var Stats to find and interpret the mean and standard deviation.
Calls, x01234
P(x)0.100.250.350.200.10
Section 6.2

The Binomial Probability Distribution

Recognize binomial settings and compute binomial probabilities with technology.

Quick reference

  • A binomial experiment must satisfy four conditions.
    • There is a fixed number of trials, \(n\).
    • Each trial has two outcomes labeled success and failure, the trials are independent, and the success probability \(p\) remains constant.
    • Sampling without replacement can be treated as approximately independent when the sample is no more than 5% of a large population.
  • Define the binomial variables before calculating.
    • \(n\) is the number of trials, \(p\) is the success probability, \(q=1-p\) is the failure probability, and \(X\) counts successes.
    • State what success means in context; it is simply the outcome being counted, not necessarily a desirable result.
  • The binomial probability formula shows the probability structure.
    • \(P(X=x)=\binom{n}{x}p^xq^{n-x}\). The combination counts where the successes can occur.
    • Use the formula for context and the TI-84 for routine probability calculations.
  • Translate probability wording before choosing a calculator command.
    • binompdf finds the probability of one exact count. binomcdf accumulates probabilities from 0 through its final argument.
    • Exactly \(k\): \(P(X=k)\), so use binompdf(n,p,k).
    • At most or no more than \(k\): \(P(X\le k)\), so use binomcdf(n,p,k).
    • Fewer than or less than \(k\): \(P(X\lt k)=P(X\le k-1)\), so use binomcdf(n,p,k-1).
    • More than or greater than \(k\): \(P(X\gt k)=1-P(X\le k)\), so use 1-binomcdf(n,p,k).
    • At least \(k\): \(P(X\ge k)=1-P(X\le k-1)\), so use 1-binomcdf(n,p,k-1).
    • Between \(a\) and \(b\), inclusive: use binomcdf(n,p,b)-binomcdf(n,p,a-1).
    • Strictly between \(a\) and \(b\): use binomcdf(n,p,b-1)-binomcdf(n,p,a).
  • A binomial distribution has mean \(\mu=np\) and standard deviation \(\sigma=\sqrt{npq}\).
    • The mean is the expected number of successes over many repetitions of the whole experiment; it need not be a whole number.
    • A count more than about 2 standard deviations from the mean may be considered unusual. Use probabilities when the question gives a specific unusual-event cutoff.
  • The binomial shape depends on \(n\) and \(p\).
    • When \(p=0.5\), the distribution is symmetric. Small \(p\) tends to skew right, and large \(p\) tends to skew left.
    • As \(n\) grows and both \(np\) and \(nq\) grow, the distribution becomes more bell-shaped.
Example 1. A basketball player makes \(70\%\) of free throws and shoots \(8\) free throws. Identify \(n\) and \(p\).
Example 2. Use binomial notation to compute the probability of exactly \(3\) successes in \(10\) trials when \(p=0.40\).
Example 3. Use the binomial distribution graph. For \(X\sim\operatorname{Binomial}(8,0.35)\), near which value should the highest bars occur?

Binomial Distribution: n = 8, p = 0.35

Binomial distribution bar chart for n equals 8 and p equals 0.35 with highest bars near 2 and 3 successes Number of Successes x Probability 012345678

The most likely values are near the mean np = 2.8.

Example 4. For \(X\sim\operatorname{Binomial}(12,0.25)\), what TI-84 command gives \(P(X\le 4)\), meaning "at most \(4\)"?
Example 5. For \(X\sim\operatorname{Binomial}(12,0.25)\), how can \(P(X\ge 5)\), meaning "at least \(5\)," be found using the complement?
Example 6. For \(X\sim\operatorname{Binomial}(12,0.25)\), what commands find \(P(3\lt X\lt 7)\)?
Example 7. For \(X\sim\operatorname{Binomial}(12,0.25)\), find the mean and standard deviation.
Example 8. Decide whether each setting is binomial. (a) A goalie attempts 20 penalty saves with a constant 0.42 save probability. (b) A goalie keeps attempting saves until the first goal is allowed. (c) Thirty patients receive a drug, but their success probabilities differ by dosage.
Example 9. For \(X\sim\operatorname{Binomial}(10,0.30)\), describe the shape. What change would make a binomial distribution more bell-shaped?
Example 10. A poll has \(n=250\) and \(p=0.45\). Find the expected count and standard deviation. Would 90 successes be unusual by the 2-standard-deviation guideline?
Example 11. For \(X\sim\operatorname{Binomial}(12,0.25)\), find each probability. (a) Fewer than 3 successes. (b) More than 4 successes.
Example 12. An airline reports that each flight arrives on time with probability 0.80. For 25 independent flights, find the probability that between 14 and 16 flights, inclusive, arrive on time. Interpret the result in 100 repeated samples of 25 flights.

Module 7: Normal Distributions

Students use normal distribution properties, normal probabilities, inverse normal values, and normality checks.

Section 7.1

Properties of the Normal Distribution

Understand normal curves, z-scores, uniform distributions, and area interpretations.

Quick reference

  • A continuous probability density curve represents probabilities by area.
    • The total area under the curve is 1, and the area over an interval equals the probability that the variable falls in that interval.
    • For a continuous variable, a single exact value has area and probability 0, so \(P(X\lt a)=P(X\le a)\).
  • A continuous uniform distribution has constant height over its interval.
    • Every equal-width subinterval has the same probability. Probability = interval length / total length.
    • For a uniform distribution from \(a\) to \(b\), the rectangle's height is \(1/(b-a)\).
  • A normal distribution is bell-shaped, symmetric, and determined by \(\mu\) and \(\sigma\).
    • The mean, median, and mode are equal at the center. Half the area lies on each side of the mean, and the curve approaches but never touches the horizontal axis.
    • Changing \(\mu\) shifts the center. A larger \(\sigma\) makes the curve wider and lower; a smaller \(\sigma\) makes it narrower and taller.
    • The inflection points occur at \(\mu-\sigma\) and \(\mu+\sigma\), where the curve changes bending direction.
  • A z-score standardizes a normal value.
    • \(z=\frac{x-\mu}{\sigma}\) tells how many standard deviations \(x\) is above or below the mean.
    • The standard normal distribution has \(\mu=0\) and \(\sigma=1\). Standardizing changes the scale, not the corresponding area.
  • Normal distributions satisfy the bell-shaped condition for the Empirical Rule reviewed in Section 3.2.
    • Refer to the Section 3.2 visual and examples for the 68-95-99.7 estimates.
    • Use exact normal calculator methods in Section 7.2 when cutoffs are not whole numbers of standard deviations from the mean.
Example 1. A normal distribution has mean \(50\) and standard deviation \(6\). Find the z-score for \(x=62\).
Example 2. A normal distribution has mean \(100\) and standard deviation \(15\). What interval is within \(1\) standard deviation?
Example 3. What is the total area under a normal curve?
Example 4. A friend is uniformly distributed from 0 to 30 minutes late. Find the probability the friend is between 15 and 20 minutes late and the probability the friend is at least 22 minutes late.

Uniform Arrival-Time Model

015202230Minutes late1/30

A constant-height rectangle extends from 0 to 30 minutes, with the interval from 15 to 20 minutes shaded.

Example 5. A normal curve is centered at 530, and adjacent inflection points are labeled 528 and 532. Identify \(\mu\) and \(\sigma\).
Example 6. Normal Curve A has \(\mu=9\), \(\sigma=4\). Normal Curve B has \(\mu=16\), \(\sigma=1\). Which curve is farther right, and which is narrower and taller?
Example 7. For pregnancy lengths, the area to the left of 250 days is 0.1587. Give two interpretations.
Section 7.2

Applications of the Normal Distribution

Use TI-84 normalcdf and invNorm to compute probabilities and cutoff values.

Quick reference

  • Start by sketching or naming the region under the normal curve.
    • Less than shades left, greater than shades right, and between shades the region between two cutoffs.
    • Probability is area, so the answer must be between 0 and 1. Use symmetry and the cutoff's location to check whether the result is reasonable.
  • Use normalcdf(lower,upper,mean,standard deviation) to find normal probabilities.
    • For less than \(a\), use a very large negative lower bound and upper bound \(a\). For greater than \(a\), use lower bound \(a\) and a very large positive upper bound.
    • For between \(a\) and \(b\), enter the two cutoffs in increasing order. For two tails, calculate each tail and add or use a complement when easier.
    • For standard-normal z-scores, use mean 0 and standard deviation 1.
  • Use invNorm(left-tail area,mean,standard deviation) to find a cutoff from an area.
    • A percentile is already a left-tail area. For a right-tail area \(r\), enter \(1-r\).
    • For the middle \(C\)% of a symmetric normal distribution, split the remaining area equally between the two tails, then find both cutoff percentiles.
    • Use mean 0 and standard deviation 1 for z-cutoffs, or enter the original \(\mu\) and \(\sigma\) to obtain raw-value cutoffs directly.
  • The notation \(z_\alpha\) identifies a standard-normal right-tail cutoff.
    • \(z_\alpha\) is the z-score with area \(\alpha\) to its right, so the area to its left is \(1-\alpha\).
    • On a TI-84, use invNorm(1-alpha,0,1). For \(z_{\alpha/2}\), use left-tail area \(1-\alpha/2\); the middle area between \(-z_{\alpha/2}\) and \(z_{\alpha/2}\) is \(1-\alpha\).
  • Interpret the calculator result in context.
    • A probability describes one randomly selected observation; the same decimal can be interpreted as an approximate long-run proportion or percentage.
    • A percentile cutoff is a value with the stated percentage of observations at or below it.
Example 1. Let \(X\) be normal with \(\mu=70\) and \(\sigma=8\). Use a TI-84 to find \(P(X\lt82)\).
Example 2. Use the shaded normal curve and a TI-84 to find \(P(65\lt X\lt80)\) when \(\mu=70\) and \(\sigma=8\).

Shaded Normal Probability

Normal Model: mean 70, standard deviation 8657080

The normal curve has mean 70 and standard deviation 8. The area under the curve between 65 and 80 is shaded.

Example 3. Let \(X\) be normal with \(\mu=70\) and \(\sigma=8\). Use a TI-84 to find the 90th percentile.
Example 4. If the calculator gives \(P(X\gt90)=0.0228\), interpret the answer.
Example 5. Find the standard-normal area to the right of \(z=-0.17\). Give the TI-84 command and result.
Example 6. Let \(X\) be normal with \(\mu=50\) and \(\sigma=8\). Find \(P(34\lt X\lt62)\).
Example 7. Find the combined standard-normal area below \(z=-1.96\) and above \(z=1.96\).
Example 8. Incubation times are normal with mean 22 days and standard deviation 1 day. Find the cutoffs for the middle 95%.
Example 9. Find \(z_{0.08}\) and explain what its subscript means.
Section 7.3

Assessing Normality

Use graphs and normal probability plots to decide whether normal methods are reasonable.

Quick reference

  • Assess normality with graphs rather than expecting perfect normal data.
    • A roughly bell-shaped, symmetric histogram with one main peak supports a normal model.
    • Strong skewness, multiple peaks, large gaps, or clear outliers are warnings against a normal model. A boxplot can help reveal skewness and outliers but does not show the full shape.
  • A normal probability plot compares ordered observations with expected normal z-scores.
    • Points that follow an approximately straight line support a normal model.
    • Systematic curvature suggests skewness or another nonnormal shape. A point far from the line may indicate an outlier.
    • To construct the plot, order the observations, calculate \(f_i=(i-0.375)/(n+0.25)\), find each expected score with invNorm(fi,0,1), and plot observed values against expected z-scores.
  • Use the normal-probability-plot critical-value table for the correlation check.
    • Find the correlation between the ordered observations and their expected z-scores, then find the critical value for \(n\).
    • For more than 30 observations, use the \(n=30\) critical value, following the homework convention.
    • If the correlation is greater than the critical value, the plot is sufficiently linear to support normality. If it is not greater, the data do not pass that normality check.
  • Use all available evidence and context.
    • A small sample can make a histogram jagged, while a very large sample can reveal minor departures from normality. Focus on departures that matter for the intended method.
    • Normality checks decide whether normal-based methods are reasonable; they do not prove that the population is exactly normal.
  • Technology can create the required displays.
    • StatCrunch is useful for normal probability plots, histograms, and larger data sets.
    • On a TI-84, enter the ordered observations in L1 and expected z-scores in L2. A normal probability plot can be selected in STAT PLOT; LinReg(ax+b) L1,L2 gives the correlation when diagnostics are on. Compare that correlation with the quick-reference critical value.
Critical Values for Normal Probability Plots
Sample size, nCritical valueSample size, nCritical value
50.880160.941
60.888170.944
70.898180.946
80.906190.949
90.912200.951
100.918210.952
110.923220.954
120.928230.956
130.932240.957
140.935250.959
150.939300.960
Example 1. Use the normal probability plot. What does this suggest about normality?

Normal Probability Plot

Normal probability plot with points close to a straight line Normal Probability Plot Data value

The points are close to a straight line, so a normal model appears reasonable.

Example 2. A histogram is strongly skewed right with several outliers. Are normal methods automatically reasonable?
Example 3. What graph is specifically designed to assess whether data are approximately normal?
Example 4. Does a data set have to be perfectly normal for normal methods to be useful?
Example 5. A normal probability plot for \(n=16\) observations has correlation 0.962. Use the quick-reference table to determine whether the sample passes the correlation check for normality.
Example 6. A histogram is roughly symmetric and bell-shaped, but its normal probability plot has one point far from the line. What should be reported?
Example 7. The observed values and their expected z-scores are shown for \(n=8\). Enter the columns in L1 and L2, use LinReg(ax+b) L1,L2, and compare the correlation with the quick-reference critical value. Does the sample pass the normality check?
Observed value23457101628
Expected z-score-1.41-0.84-0.47-0.150.150.470.841.41

Curved Normal Probability Plot

Observed valueExpected z-score

The points bend systematically away from the dashed straight reference line, especially for the largest observed values.

Module 8: Sampling Distributions

Students study sampling distributions for sample means and sample proportions.

Section 8.1

Distribution of the Sample Mean

Use the sampling distribution of \(\bar{x}\) and the Central Limit Theorem.

Quick reference

  • The sampling distribution of \(\bar{x}\) is the distribution of sample means from all possible random samples of the same size \(n\).
    • The population distribution describes individual values; one sample has its own data distribution; the sampling distribution describes how \(\bar{x}\) varies from sample to sample.
    • A simulation approximates the sampling distribution by repeatedly taking samples, computing each mean, and graphing those means.
  • The sampling distribution is centered at the population mean and has less spread than individual values.
    • \(\mu_{\bar{x}}=\mu\). The sample mean is an unbiased estimator because its long-run mean equals the population mean.
    • \(\sigma_{\bar{x}}=\frac{\sigma}{\sqrt{n}}\). This standard deviation of sample means is called the standard error.
    • As \(n\) increases, standard error decreases, so larger samples produce means that cluster more tightly around \(\mu\).
  • Check independence and shape before using a normal model for \(\bar{x}\).
    • Use a simple random sample or a design that produces representative, approximately independent observations. When sampling without replacement, check \(n\le0.05N\).
    • If the population is normal, the sampling distribution of \(\bar{x}\) is normal for any sample size.
    • If the population is not normal, the Central Limit Theorem says the sampling distribution becomes approximately normal as \(n\) grows. \(n\ge30\) is a common introductory guideline, but strong skewness or outliers may require a larger sample.
  • Use the sampling-distribution parameters, not the population spread, in probability calculations.
    • For probabilities involving one individual value \(X\), use mean \(\mu\) and standard deviation \(\sigma\).
    • For probabilities involving a sample mean \(\bar{x}\), use mean \(\mu\) and standard error \(\sigma/\sqrt{n}\).
    • On the TI-84, use normalcdf(lower,upper,mean,standard deviation), entering \(\mu\) for the mean and \(\sigma/\sqrt{n}\) for the standard deviation. Interpret the result as a proportion of samples or a probability for a randomly selected sample.
Example 1. Use the comparison figure. How does the sampling distribution of \(\bar{x}\) compare with the population distribution?

Population Distribution versus Sampling Distribution

Comparison of a right-skewed population distribution and a narrower approximately normal sampling distribution of sample means Population vs. Sample Means Population values Sample means meansame center smaller standard error

A right-skewed population distribution has a peak toward the left and a long right tail. The sampling distribution of sample means is approximately normal, centered at the population mean, and has smaller spread.

Example 2. A population has \(\mu=80\), \(\sigma=12\), and samples of size \(36\). Find \(\mu_{\bar{x}}\) and \(\sigma_{\bar{x}}\).
Example 3. For the same setting, what TI-84 command finds \(P(\bar{x}\lt 83)\)?
Example 4. What happens to the standard error as sample size increases?
Example 5. Why is the Central Limit Theorem useful?
Example 6. A population is strongly skewed right. Compare the expected sampling-distribution shapes for samples of size \(n=4\) and \(n=35\).
Example 7. Pregnancy lengths are normal with \(\mu=266\) days and \(\sigma=16\) days. Compare the TI-84 setups for the probability that one pregnancy is under 260 days and the probability that the mean of \(n=16\) pregnancies is under 260 days.
Example 8. A population has \(\mu=200\) and \(\sigma=10\). Without calculating exact values, order these probabilities from least to greatest: an individual value from 195 to 205, a sample mean with \(n=10\) in that interval, and a sample mean with \(n=20\) in that interval.
Example 9. Which procedure correctly simulates the sampling distribution of the sample mean for samples of size \(n=20\)? (a) Take one random sample of 20 observations and graph those observations. (b) Repeatedly take random samples of 20 observations, calculate each sample mean, and graph the collection of means. (c) Repeatedly take samples of changing sizes and graph every individual observation.
Section 8.2

Distribution of the Sample Proportion

Use the sampling distribution of \(\hat{p}\) and check normal approximation conditions.

Quick reference

  • The sample proportion is \(\hat{p}=x/n\), where \(x\) is the number of sampled individuals with the characteristic.
    • The population proportion \(p\) is a fixed parameter; \(\hat{p}\) varies from sample to sample and estimates \(p\).
    • The sampling distribution of \(\hat{p}\) describes the proportions from all possible random samples of the same size.
  • The sampling distribution is centered at \(p\) and becomes less variable as \(n\) increases.
    • \(\mu_{\hat{p}}=p\), so the sample proportion is an unbiased estimator of the population proportion.
    • \(\sigma_{\hat{p}}=\sqrt{\frac{p(1-p)}{n}}\). This is the standard error when the population proportion is used in a sampling-distribution problem.
  • Check the sampling conditions before using a normal model for \(\hat{p}\).
    • Use a simple random sample or another representative random process. For sampling without replacement, check \(n\le0.05N\).
    • For this course's homework, check \(np(1-p)\ge10\). If this value is below 10, the sampling distribution may be too skewed for the normal approximation.
    • When solving for a required sample size, isolate \(n\), round the result up, and subtract the current sample size if the question asks how many additional individuals are needed.
  • Use the proportion mean and standard error in normal probability calculations.
    • On the TI-84, use normalcdf(lower,upper,p,standard deviation), entering \(\sqrt{p(1-p)/n}\) for the standard deviation.
    • Interpret the result as the probability that a random sample produces a proportion in the stated range, or as the long-run proportion of such samples.
Example 1. Let \(p=0.40\) and \(n=100\). Find the mean and standard deviation of \(\hat{p}\).
Example 2. Check the normal approximation conditions for \(p=0.40\), \(n=100\).
Example 3. What TI-84 command finds \(P(\hat{p}\lt 0.45)\) when \(p=0.40\), \(n=100\), and standard error is \(0.049\)?
Example 4. If \(np(1-p)=7\), what concern should be noted?
Example 5. In a sample of 1400 adults, 154 report being afraid to fly. Find the sample proportion. Is it required to equal a previously reported population proportion of 0.10?
Example 6. A population has \(N=20{,}000\), \(p=0.10\), and a simple random sample has \(n=400\). Check the conditions and describe the sampling distribution of \(\hat{p}\).
Example 7. Suppose \(p=0.82\) and \(n=100\). Find \(P(\hat{p}\gt0.88)\) and interpret it.
Example 8. A historical proportion is \(p=0.10\). In a new random sample of \(n=1200\), 132 people have the characteristic. Explain how the sampling distribution helps decide whether the sample proportion is surprising.
Example 9. A researcher already plans to sample 50 adults. How many additional adults are needed for the sampling distribution of \(\hat{p}\) to meet \(np(1-p)\ge10\) if (a) \(p=0.20\) and (b) \(p=0.25\)?

Module 9: Confidence Intervals

Students estimate population proportions and means using confidence intervals.

Section 9.1

Estimating a Population Proportion

Use one-proportion confidence intervals and interpret them correctly.

Quick reference

  • A point estimate is a sample statistic used to estimate a population parameter.
    • For a population proportion \(p\), the point estimate is \(\hat{p}=x/n\). The variable must have two outcomes after defining success and failure.
    • A confidence interval has the form point estimate +/- margin of error. Its midpoint is the point estimate, and \(E=(\text{upper}-\text{lower})/2\).
  • The confidence level describes the long-run success rate of the interval method.
    • The population proportion is fixed but unknown. Different random samples produce different sample proportions and therefore different intervals.
    • If many random samples were taken and an interval were built from each, about \(C\)% of those intervals would capture the fixed population proportion.
    • Once one interval is computed, the fixed proportion either is or is not inside it. Say, 'We are \(C\)% confident that the interval captures the population proportion,' not that there is a \(C\)% probability the parameter is inside.
  • Check conditions for a one-proportion z-interval.
    • Use a random or representative sample and, when sampling without replacement, check \(n\le0.05N\).
    • For this course's homework, check \(n\hat{p}(1-\hat{p})\ge10\) using the observed sample proportion.
  • For formula context, \(\hat{p}\pm z^*\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}\).
    • Higher confidence uses a larger critical value and produces a wider interval when other information is fixed.
    • A larger sample size reduces standard error and produces a narrower interval when the confidence level and sample proportion are fixed.
  • The critical value \(z^*=z_{\alpha/2}\) captures the middle \((1-\alpha)100\%\) of the standard normal distribution.
    • On the TI-84, use invNorm(1-alpha/2,0,1). Common values are 1.645 for 90%, 1.960 for 95%, and 2.576 for 99% confidence.
    • Each tail has area \(\alpha/2\), so the positive critical value has left-tail area \(1-\alpha/2\).
  • Choose a sample size large enough to achieve the requested margin of error \(E\).
    • With a prior estimate \(\tilde{p}\), use \(n=\tilde{p}(1-\tilde{p})(z^*/E)^2\). Without a prior estimate, use \(n=0.25(z^*/E)^2\).
    • Write a percent margin of error as a decimal and always round the calculated sample size up to the next whole number.
  • TI-84 1-PropZInt workflow:
    • Open STAT → TESTS → 1-PropZInt. Enter the number of successes \(x\), sample size \(n\), and confidence level, then calculate.
    • Read the interval and \(\hat{p}\), then write a contextual interpretation naming the population and the characteristic.
Example 1. In a sample of \(250\) adults, \(142\) support a proposal. Find \(\hat{p}\).
Example 2. A sample has \(x=142\) supporters out of \(n=250\). Use TI-84 1-PropZInt for a \(95\%\) confidence interval and interpret the output.
Example 3. A \(95\%\) confidence interval is \((0.51,0.63)\). Interpret it in context.
Example 4. Is it correct to say there is a \(95\%\) probability the fixed population proportion is in this computed interval?
Example 5. Start to finish: In a random sample of \(420\) voters, \(231\) favor a proposal. Build and interpret a \(95\%\) confidence interval for the population proportion.
Example 6. A confidence interval is (0.141, 0.679). Find the point estimate and margin of error.
Example 7. With the same sample size and sample proportion, order 82%, 88%, 94%, and 99% confidence intervals from narrowest to widest.
Example 8. If 100 different 91% confidence intervals are constructed under the model conditions, about how many should capture the population proportion? Must exactly that many capture it?
Example 9. Find the critical value \(z^*\) for a 98% confidence interval.
Example 10. Find the minimum sample size for a 95% confidence interval with margin of error 0.03 (a) using a prior estimate of 0.40 and (b) without a prior estimate.
Section 9.2

Estimating a Population Mean

Use one-sample t-intervals and interpret them correctly.

Quick reference

  • The sample mean \(\bar{x}\) is the point estimate for a population mean \(\mu\).
    • A mean confidence interval has the form \(\bar{x}\pm E\). Its midpoint is \(\bar{x}\), and its margin of error is half the interval width.
    • Use a one-sample t-interval when the population standard deviation \(\sigma\) is unknown and is estimated with the sample standard deviation \(s\).
  • The t-distribution accounts for the additional uncertainty from estimating \(\sigma\).
    • Degrees of freedom tell how many sample values can vary freely after using the sample to estimate its mean. For one sample, \(df=n-1\): once the mean and \(n-1\) values are fixed, the last value is forced to make the deviations balance around the mean.
    • Degrees of freedom select the appropriate t-distribution and critical value. Smaller \(df\) means more uncertainty, heavier tails, and a larger critical value.
    • The t-distribution is symmetric and bell-shaped. As degrees of freedom increase, it approaches the standard normal distribution.
  • The critical value \(t^*=t_{\alpha/2}\) depends on the confidence level and degrees of freedom.
    • For a \((1-\alpha)100\%\) interval, use the t-table or invT(1-alpha/2,df) with \(df=n-1\).
    • The interval extends \(t^*\) standard errors below and above the sample mean.
  • Check conditions for a one-sample t-interval.
    • Use a random or representative sample and check \(n\le0.05N\) when sampling without replacement.
    • For a small sample, the population should be approximately normal with no strong skewness or outliers. Larger samples make t-procedures more robust, but severe outliers still matter.
  • For formula context, \(\bar{x}\pm t^*\frac{s}{\sqrt{n}}\).
    • Higher confidence increases \(t^*\) and the margin of error. Increasing \(n\) decreases the standard error and margin of error.
    • Interpret the interval as a plausible range for the population mean in the original units, not as a range containing a stated percentage of individual observations.
  • Use confidence wording because the population mean is fixed while the interval varies from sample to sample.
    • In repeated sampling, a \(C\)% confidence-interval method captures the fixed population mean in about \(C\)% of the intervals it produces.
    • After one interval is calculated, the mean either is or is not inside it. Say, 'We are \(C\)% confident that the interval captures the population mean,' not that there is a \(C\)% probability the fixed mean is inside.
  • For planning, estimate the sample size with \(n=(z^*\sigma/E)^2\).
    • Use a known or reasonable planning value for \(\sigma\); a standard deviation from an earlier study may be used when the population standard deviation is unavailable.
    • Use the z critical value because the t critical value depends on the sample size being found, and always round the result up.
  • TI-84 TInterval workflow:
    • Choose Data when raw observations are in a list, or Stats when \(\bar{x}\), \(s\), and \(n\) are given. Enter the confidence level and calculate.
    • Read the interval and degrees of freedom, then state: 'We are \(C\)% confident that the population mean [context] is between [lower] and [upper] [units].'
Example 1. A sample has \(n=18\). What are the degrees of freedom for a one-sample t-interval?
Example 2. Use TI-84 TInterval with summary statistics \(n=18\), \(\bar{x}=14.6\), \(s=3.8\), and confidence level \(90\%\). Interpret the interval.
Example 3. A \(90\%\) confidence interval for mean wait time is \((12.4,16.8)\) minutes. Interpret it.
Example 4. Why should outliers be checked for a small-sample t-interval?
Example 5. Start to finish: A random sample of \(24\) wait times has \(\bar{x}=18.4\) minutes and \(s=4.2\) minutes. A boxplot shows no strong skew or outliers. Build and interpret a \(95\%\) confidence interval for the population mean wait time.
Example 6. A mean confidence interval is (21, 25). Find the point estimate and margin of error.
Example 7. Two 96% t-intervals use the same sample mean and standard deviation, but one has \(n=13\) and the other has \(n=26\). Which is narrower?
Example 8. A 95% confidence interval for mean reading time is 12.4 to 16.8 minutes. Is it correct to say 95% of individual reading times lie in this interval?
Example 9. Find the critical value \(t^*\) for a 90% confidence interval based on a sample of 13 observations.
Example 10. An earlier study found a standard deviation of 12 minutes. Estimate the minimum sample size needed for a 95% confidence interval for the population mean with margin of error 2 minutes.

Module 10: Hypothesis Testing

Students set up and run hypothesis tests for population proportions and means using correct statistical wording.

Section 10.1

The Language of Hypothesis Testing

Use hypothesis-test vocabulary and write correct conclusions.

Quick reference

  • A hypothesis test evaluates a claim about a population parameter using sample evidence.
    • Write hypotheses with parameters such as \(p\), \(\mu\), or \(\sigma\), not sample statistics such as \(\hat{p}\), \(\bar{x}\), or \(s\).
    • The null hypothesis \(H_0\) contains equality and represents the starting status or claimed value. The alternative \(H_a\) states the change or difference the evidence is meant to support.
  • The alternative hypothesis determines the test direction.
    • \(\lt\) gives a left-tailed test, \(\gt\) gives a right-tailed test, and \(\ne\) gives a two-tailed test. Left- and right-tailed tests are also called one-tailed tests.
    • Words such as decreased or less suggest left-tailed; increased, more, or greater suggest right-tailed; changed or different suggest two-tailed.
  • The P-value measures evidence against \(H_0\).
    • It is the probability, assuming \(H_0\) is true, of obtaining a sample result at least as extreme in the direction of \(H_a\) as the observed result.
    • Smaller P-values give stronger evidence against \(H_0\). A P-value is not the probability that \(H_0\) is true.
  • The P-value and critical-value approaches use the same evidence and make the same decision.
    • P-value approach: reject \(H_0\) when P-value \(\le\alpha\); otherwise, fail to reject \(H_0\).
    • Critical-value approach: use \(\alpha\) and the direction of \(H_a\) to mark the rejection region. Reject \(H_0\) when the test statistic falls beyond the critical value in that region.
    • When the test statistic is beyond the critical value, its P-value area is no larger than \(\alpha\), so both approaches reject. Otherwise, both approaches fail to reject.
    • Fail to reject does not mean accept or prove \(H_0\); the evidence may simply be insufficient.
    • A smaller \(\alpha\) makes rejection harder and lowers the chance of a Type I error.
  • A testing decision can be wrong.
    • Type I error: reject a true \(H_0\). Its probability is \(\alpha\). Describe the false conclusion in the problem's context.
    • Type II error: fail to reject a false \(H_0\). Describe the real change or difference the test failed to detect.
  • Write the conclusion in terms of the original claim.
    • When rejecting \(H_0\), say there is sufficient evidence for the alternative claim.
    • When failing to reject \(H_0\), say there is not sufficient evidence for the alternative claim. If the original claim is the null, say the data do not provide sufficient evidence against that claim; do not say the claim was proven true.
Actual situationFail to reject \(H_0\)Reject \(H_0\)
\(H_0\) is trueCorrect decision - no error.
The test does not claim a change when none exists.
Type I error.
The test claims a change or difference when none actually exists.
\(H_0\) is false
\(H_a\) is true
Type II error.
The test misses a real change or difference.
Correct decision - no error.
The test detects a real change or difference.

Critical-Value and P-Value Approaches

Two aligned right-tailed normal curves comparing the critical-value and P-value approaches

For a right-tailed test with alpha 0.05, the top curve marks the critical value 1.645 and shades the rejection region to its right. The observed test statistic 2.10 falls in that region. The bottom curve shades the P-value area to the right of 2.10, approximately 0.0179, which is less than alpha. Both approaches reject the null hypothesis.

Example 1. A claim says the population proportion is greater than \(0.40\). Write the alternative hypothesis.
Example 2. If \(H_a:\mu\lt 25\), what type of test is this?
Example 3. If \(P\text{-value}=0.032\) and \(\alpha=0.05\), what is the decision?
Example 4. If the P-value is large, should we say we accept \(H_0\)?
Example 5. In a medical screening study, \(H_0\) says the test has the advertised accuracy. What kind of error is rejecting \(H_0\) when the advertised accuracy is actually true?
Example 6. A manager tests \(H_0:\mu=7.9\) against \(H_a:\mu\lt7.9\). Describe a Type II error in context.
Example 7. Three years ago, the population standard deviation of monthly cell phone bills was $48.79. A researcher tests \(H_0:\sigma=48.79\) against \(H_a:\sigma\lt48.79\) and rejects \(H_0\). State the conclusion in context.
Example 8. If a Type I error would have severe consequences, which common significance level is the most conservative: 0.10, 0.05, or 0.01?
Section 10.2

Hypothesis Tests for a Population Proportion

Use one-proportion z-tests with TI-84 and state conclusions correctly.

Quick reference

  • Use a one-proportion z-test for a claim about one population proportion \(p\).
    • Write \(H_0:p=p_0\). Choose \(H_a:p\lt p_0\), \(p\gt p_0\), or \(p\ne p_0\) from the claim's wording.
    • Use the population parameter \(p\) in the hypotheses, not the observed sample proportion \(\hat{p}\).
  • Check the one-proportion test conditions using the null value.
    • Use a random or representative sample and check \(n\le0.05N\) when sampling without replacement.
    • For this course's homework, check \(np_0(1-p_0)\ge10\). Test conditions use the null proportion \(p_0\), unlike interval conditions, which use the observed sample proportion.
  • The one-proportion test statistic compares the observed proportion with the null proportion.
    • For formula context, \(z=\frac{\hat{p}-p_0}{\sqrt{p_0(1-p_0)/n}}\).
    • The P-value is the null-model tail area at least as extreme as the observed \(z\), using the direction in \(H_a\).
  • Use either the P-value approach or the critical-value approach for a one-proportion z-test.
    • P-value approach: reject \(H_0\) when the calculator's P-value is no larger than \(\alpha\).
    • Critical-value approach: for a left-tailed test use invNorm(alpha,0,1); for a right-tailed test use invNorm(1-alpha,0,1); for a two-tailed test use the positive and negative values from invNorm(1-alpha/2,0,1).
    • Reject when the observed \(z\) falls beyond the critical value in the rejection region. Both approaches must give the same decision.
  • TI-84 1-PropZTest workflow:
    • Open STAT → TESTS → 1-PropZTest. Enter \(p_0\), successes \(x\), sample size \(n\), and the alternative symbol.
    • Read \(z\), the P-value, and \(\hat{p}\). Compare the P-value with \(\alpha\); do not decide from whether \(\hat{p}\) is merely above or below \(p_0\).
  • Use the Draw option in 1-PropZTest to see the P-value graph.
    • After entering the 1-PropZTest information and selecting the alternative symbol, highlight Draw instead of Calculate and press ENTER.
    • The calculator draws the standard normal curve, shades the P-value area, and displays the test statistic and P-value. A less-than alternative shades the left tail, a greater-than alternative shades the right tail, and a not-equal alternative shades both tails.
    • The Draw screen illustrates the P-value approach. It does not mark the critical z-value, so find that separately with invNorm when the critical-value approach is required.
  • State the conclusion with evidence wording and context.
    • Reject \(H_0\): 'There is sufficient evidence to conclude that [alternative claim about the population proportion].'
    • Fail to reject \(H_0\): 'There is not sufficient evidence to conclude that [alternative claim].' Do not say the null is true or that no difference exists.
  • Statistical significance does not guarantee practical importance.
    • A very large sample can make a small departure from \(p_0\) statistically significant. Report the observed size of the difference and its context when practical importance matters.
Example 1. A claim says fewer than \(30\%\) of students work full time. Write \(H_0\) and \(H_a\).
Example 2. For \(H_0:p=0.30\), \(n=120\), check the large-count conditions.
Example 3. A sample of \(120\) students has \(27\) who work full time. Test the claim \(p\lt 0.30\) at \(\alpha=0.05\) using TI-84 1-PropZTest.
Example 4. A test gives \(P\text{-value}=0.081\) with \(\alpha=0.05\). What is the decision?
Example 5. State the conclusion for a failed rejection when the claim was \(p\lt 0.30\).
Example 6. Start to finish: A college claims fewer than \(40\%\) of students buy a printed textbook. In a random sample of \(180\) students, \(62\) bought a printed textbook. Test the claim at \(\alpha=0.05\).
Example 7. Order these P-values from weakest to strongest evidence against \(H_0\): 0.048, 0.013, 0.008, 0.036.
Example 8. A test of \(H_0:p=0.60\) gives P-value 0.18. Interpret this P-value without stating a decision.
Example 9. A very large study finds \(\hat{p}=0.503\) significantly different from \(p_0=0.500\). What additional question should be asked?
Example 10. Return to the left-tailed one-proportion z-test in Example 3. Use the Draw option in TI-84 1-PropZTest. Describe the graph, report the displayed test statistic and P-value, and state the decision at \(\alpha=0.05\). How does this agree with the critical-value approach?
Section 10.3

Hypothesis Tests for a Population Mean

Use one-sample t-tests with TI-84 and state conclusions correctly.

Quick reference

  • Use a one-sample t-test for a claim about one population mean when \(\sigma\) is unknown.
    • Write \(H_0:\mu=\mu_0\). Choose a left-, right-, or two-tailed alternative from the claim.
    • Use the population mean \(\mu\) in the hypotheses, not the sample mean \(\bar{x}\). Degrees of freedom are \(df=n-1\).
  • Check the one-sample t-test conditions.
    • Use a random or representative sample and check \(n\le0.05N\) when sampling without replacement.
    • For a small sample, verify approximate normality and no strong outliers with the data, histogram, boxplot, or normal probability plot. Larger samples are more robust, but extreme outliers can still distort the test.
  • The t statistic measures the sample mean's distance from the null mean in standard-error units.
    • For formula context, \(t=\frac{\bar{x}-\mu_0}{s/\sqrt{n}}\).
    • The P-value is the t-distribution tail area at least as extreme as the observed statistic, using \(df=n-1\) and the direction in \(H_a\).
  • Tail direction controls the critical value and the P-value area.
    • For a right-tailed test use \(t_{\alpha}\); for a left-tailed test use \(-t_{\alpha}\); for a two-tailed test use \(\pm t_{\alpha/2}\), all with \(df=n-1\).
    • Because invT uses left-tail area, enter invT(1-alpha,df) for a right critical value, invT(alpha,df) for a left critical value, or invT(1-alpha/2,df) for the positive two-tailed critical value.
    • Shade the P-value to the left for \(H_a:\mu\lt\mu_0\), to the right for \(H_a:\mu\gt\mu_0\), and in both tails for \(H_a:\mu\ne\mu_0\).
    • The P-value approach rejects when P-value \(\le\alpha\). The critical-value approach rejects when \(t\) falls beyond the critical value. Both approaches must agree.
  • TI-84 T-Test workflow:
    • Choose Data when raw observations are stored in a list, or Stats when \(\bar{x}\), \(s\), and \(n\) are given. Enter \(\mu_0\) and select the correct alternative.
    • Read \(t\), the P-value, \(\bar{x}\), and \(n\). Compare the P-value with \(\alpha\).
  • Use the Draw option in T-Test to see the P-value graph.
    • After entering the T-Test information and selecting the alternative symbol, highlight Draw instead of Calculate and press ENTER.
    • The calculator draws the t distribution, shades the P-value area, and displays the test statistic and P-value. A less-than alternative shades the left tail, a greater-than alternative shades the right tail, and a not-equal alternative shades both tails.
    • The Draw screen illustrates the P-value approach. It does not mark the critical t-value, so find that separately with invT when the critical-value approach is required.
  • Finish with a decision and contextual conclusion.
    • Reject \(H_0\): there is sufficient evidence for the alternative claim about the population mean.
    • Fail to reject \(H_0\): there is not sufficient evidence for the alternative claim. Do not say the population mean equals \(\mu_0\) or that \(H_0\) was accepted.
  • Separate statistical significance from practical significance.
    • A small P-value says the sample result would be unusual under \(H_0\); it does not say the difference \(\bar{x}-\mu_0\) is large enough to matter in practice.
    • Report the estimated difference and its units when judging real-world importance.
Example 1. A claim says the population mean wait time is different from \(15\) minutes. Write \(H_0\) and \(H_a\).
Example 2. If \(H_a:\mu\gt42\), what type of test is this?
Example 3. A sample has \(n=16\), \(\bar{x}=43.8\), and \(s=3.2\). Test the claim \(\mu\gt42\) at \(\alpha=0.05\) using TI-84 T-Test.
Example 4. A t-test gives \(P\text{-value}=0.014\) with \(\alpha=0.05\). What is the decision?
Example 5. State the conclusion for rejecting \(H_0\) when the claim was \(\mu\gt42\).
Example 6. Start to finish: A tutoring center claims the mean improvement is more than \(5\) points. A random sample of \(20\) students has \(\bar{x}=6.3\), \(s=2.4\), and no strong skew or outliers. Test the claim at \(\alpha=0.05\).
Example 7. A left-tailed t-test of \(H_0:\mu=20\) gives \(t=-1.90\) and P-value 0.036. Interpret the P-value and decide at \(\alpha=0.05\).
Example 8. A two-tailed mean test at \(\alpha=0.01\) has a matching 99% confidence interval that contains \(\mu_0\). What decision should the test make?
Example 9. A large-sample study finds a statistically significant mean increase of 0.02 unit. What should be considered before calling the result important?
Example 10. Find the critical value or values for each t-test: (a) right-tailed with \(\alpha=0.05\) and \(df=15\); (b) left-tailed with \(\alpha=0.10\) and \(n=10\); (c) two-tailed with \(\alpha=0.01\) and \(n=16\).
Example 11. Start to finish: A random sample of 17 completion times has mean 19.6 minutes and standard deviation 4.4 minutes, with no strong skew or outliers. Test \(H_0:\mu=21\) against \(H_a:\mu\lt21\) at \(\alpha=0.01\).
Example 12. Return to the right-tailed one-sample t-test in Example 3. Use the Draw option in TI-84 T-Test. Describe the graph, report the displayed test statistic and P-value, and state the decision at \(\alpha=0.05\). How does this agree with the critical-value approach?
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